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anonymous

  • one year ago

11 Swimming pool water can be kept free of harmful bacteria by adding aqueous sodium chlorate(I), NaOCl. This reacts with water to produce HOCl molecules which kill bacteria. OCl–(aq) + H2O(reversible) OH–(aq) + HOCl (aq) In bright sunshine, the OCl – ion is broken down by ultra-violet lighT OCL–(aq) + uv light → Cl–(aq)+ ½O2(g) Which method would maintain the highest concentration of HOCl (aq)? A acidify the pool water B add a solution of chloride ions C add a solution of hydroxide ions D bubble air through the water

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  1. anonymous
    • one year ago
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    I get the part where uv light and ocl reaction is iroreversible so B and D cannot be the option

  2. anonymous
    • one year ago
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    A?

  3. anonymous
    • one year ago
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    Yeah but how?

  4. anonymous
    • one year ago
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    As you said, B and D cannot be the answer, so it leaves C and A, C cannot be correct as adding a solution.of hydroxide ions would faviur the reaction backwards and more reactants would be produced leaving A as the only option Plus acidifying the solution means more H+ ions would be produce which would react to make more hocl hocl

  5. anonymous
    • one year ago
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    Hope this helps :)

  6. anonymous
    • one year ago
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    Thankyou!!

  7. anonymous
    • one year ago
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    And if this helped, please answer a question that i recently posted, if you know how to, badly need help in it :)

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