anonymous
  • anonymous
11 Swimming pool water can be kept free of harmful bacteria by adding aqueous sodium chlorate(I), NaOCl. This reacts with water to produce HOCl molecules which kill bacteria. OCl–(aq) + H2O(reversible) OH–(aq) + HOCl (aq) In bright sunshine, the OCl – ion is broken down by ultra-violet lighT OCL–(aq) + uv light → Cl–(aq)+ ½O2(g) Which method would maintain the highest concentration of HOCl (aq)? A acidify the pool water B add a solution of chloride ions C add a solution of hydroxide ions D bubble air through the water
Chemistry
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
I get the part where uv light and ocl reaction is iroreversible so B and D cannot be the option
anonymous
  • anonymous
A?
anonymous
  • anonymous
Yeah but how?

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anonymous
  • anonymous
As you said, B and D cannot be the answer, so it leaves C and A, C cannot be correct as adding a solution.of hydroxide ions would faviur the reaction backwards and more reactants would be produced leaving A as the only option Plus acidifying the solution means more H+ ions would be produce which would react to make more hocl hocl
anonymous
  • anonymous
Hope this helps :)
anonymous
  • anonymous
Thankyou!!
anonymous
  • anonymous
And if this helped, please answer a question that i recently posted, if you know how to, badly need help in it :)

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