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anonymous

  • one year ago

A point charge of +1.0 µC is moved in the direction of an electric field, and it has a change in electric potential difference energy of 10.0 J. What was the change in electric potential difference? 1 µC = 10^-6 C A. -1.0 × 10^8 V B. -1.0 × 10^7 V C. +1.0 × 10^7 V D. +1.0 × 10^8 V

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  1. Michele_Laino
    • one year ago
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    the requested value is: \[\Delta V = \frac{L}{q} = \frac{{10}}{{{{10}^{ - 6}}}}\]

  2. anonymous
    • one year ago
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    ok! so we get 10,000,000? so our solution is choice C?

  3. Michele_Laino
    • one year ago
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    the final potential is greter than the initial potential

  4. Michele_Laino
    • one year ago
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    yes!

  5. anonymous
    • one year ago
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    yay! thank you!!:D

  6. Michele_Laino
    • one year ago
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    :)

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