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anonymous
 one year ago
Will fan and medal
Freddie is at chess practice waiting on his opponent's next move. He notices that the 4inchlong minute hand is rotating around the clock and marking off time like degrees on a unit circle.
Part 1: How many radians does the minute hand move from 3:35 to 3:55? (Hint: Find the number of degrees per minute first.)
Part 2: How far does the tip of the minute hand travel during that time?
Part 3: How many radians on the unit circle would the minute hand travel from 0° if it were to move 3π inches?
Part 4: What is the coordinate point associated with this radian measure?
anonymous
 one year ago
Will fan and medal Freddie is at chess practice waiting on his opponent's next move. He notices that the 4inchlong minute hand is rotating around the clock and marking off time like degrees on a unit circle. Part 1: How many radians does the minute hand move from 3:35 to 3:55? (Hint: Find the number of degrees per minute first.) Part 2: How far does the tip of the minute hand travel during that time? Part 3: How many radians on the unit circle would the minute hand travel from 0° if it were to move 3π inches? Part 4: What is the coordinate point associated with this radian measure?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I just need to know if I'm right. To find the degree you would divide the degrees of a circle by the number of minutes in an hour which would be 360/60=6. So six per minute you would multiply by 5 and get 30° in 5 minutes. Now we need to find the radians by dividing 30 by 180 like this 30/180 which would give you 1/6 and the radian measure is π/6. I'm not exactly sure what to do now

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@texaschic101 can you help?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Michele_Laino can you help? Please.

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1the angular velocity of the 4inch hand is 2*pi/60= pi/30 radians/min

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1since the long minute hand travels one complete turn every 60 minutes

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1so we can write this condition: \[2\pi R = \omega R\Delta t\] where \Delta t = 60 minutes and R = 4 inches

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1\[2\pi R = \omega R60\] dividing by 60, we get: \[\omega = \frac{{2\pi }}{{60}} = \frac{\pi }{{30}}\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1so the answer for part 1, is: \[\alpha = \frac{\pi }{{30}} \times 20\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1since from 3.35 to 3.55 there are 20 minutes

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1so, after a simplification, we get: \[\alpha = \frac{{2\pi }}{3}\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1oops.. \[\alpha = \frac{{2\pi }}{3}\;radians\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Sorry my computer froze. I think I am understanding a bit more

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1now, part 2 the requested distance L, is given by the subsequent computation: \[\Large L = R\alpha = R\frac{{2\pi }}{3}\] where R = 4 inches

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The part I need help with is part 4 now

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1part 3) the requested angle is: \[\Large \beta = \frac{{3\pi }}{R}\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1and the requested coordinates are: \[\Large \left( {R,\frac{{3\pi }}{2}} \right)\] dw:1433448393972:dw

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1the longminute hand travels for a distance 3pi long, right?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1so the final position is: dw:1433449752947:dw

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1at the final position correspond an angle of 3*pi/2 radians, so the polar coordinates are: (R, 3*pi/2) being R the length of the long minute hand

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1dw:1433450239850:dw
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