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anonymous
 one year ago
Find the magnitude and direction angle θ, to the nearest tenth of a degree, for the given vector v. v = 4i  3j
anonymous
 one year ago
Find the magnitude and direction angle θ, to the nearest tenth of a degree, for the given vector v. v = 4i  3j

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\tan ^{1} \frac{ 3 }{ 4} =\Theta\ =36.8698976\] so rounding that it's about 36.9 degrees. It's magnitude is found by the pythagorean theorm... so what is that? a^2 + b^2 = c^2 16 + 9 = c^2 c= + 5 so magnitude is always positive so the answer would be 5@36.9deg
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