anonymous
  • anonymous
If 4.0 × 10^-18 J of work done on a point charge changes its electric potential difference by 25.0 V, then what is the magnitude of the charge? A. 1.6 × 10^-19 C B. 4.0 × 10^-19 C C. 1.6 × 10^-18 C D. 4.0 × 10^-18 C
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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Michele_Laino
  • Michele_Laino
the requested charge (magnitude) is: \[q = \frac{W}{{\Delta V}}\]
anonymous
  • anonymous
ok! 4.0*10^-18 / 25 ?
Michele_Laino
  • Michele_Laino
\[q = \frac{W}{{\Delta V}} = \frac{{4 \times {{10}^{ - 18}}}}{{25}}\]

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Michele_Laino
  • Michele_Laino
yes!
anonymous
  • anonymous
yay! so we get 1.6E-19? so choice A is our solution?
Michele_Laino
  • Michele_Laino
correct!
anonymous
  • anonymous
yay!! thanks!!:D
Michele_Laino
  • Michele_Laino
:)

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