## anonymous one year ago If 4.0 × 10^-18 J of work done on a point charge changes its electric potential difference by 25.0 V, then what is the magnitude of the charge? A. 1.6 × 10^-19 C B. 4.0 × 10^-19 C C. 1.6 × 10^-18 C D. 4.0 × 10^-18 C

1. Michele_Laino

the requested charge (magnitude) is: $q = \frac{W}{{\Delta V}}$

2. anonymous

ok! 4.0*10^-18 / 25 ?

3. Michele_Laino

$q = \frac{W}{{\Delta V}} = \frac{{4 \times {{10}^{ - 18}}}}{{25}}$

4. Michele_Laino

yes!

5. anonymous

yay! so we get 1.6E-19? so choice A is our solution?

6. Michele_Laino

correct!

7. anonymous

yay!! thanks!!:D

8. Michele_Laino

:)