## anonymous one year ago Two parallel plates have an electric field strength between them of 1.0 × 10^3 N/C and an electric potential difference of 50.0 V. How far apart are the plates? A. 1.0 cm B. 2.0 cm C. 5.0 cm D. 10.0 cm

1. Michele_Laino

the requested distance is; $d = \frac{{\Delta V}}{E} = \frac{{50}}{{{{10}^3}}}$

2. anonymous

ok! so 0.05 m? so that means 5.0 cm? answer choice C is our solution?

3. Michele_Laino

that's right!

4. anonymous

yay!! thank you!!:)

5. Michele_Laino

:)