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anonymous
 one year ago
The work of a student to solve a set of equations is shown:
Equation A: y = 15 − 2z
Equation B: 2y = 3 − 4z
Step 1: −2(y) = −2(15 − 2z) [Equation A is multiplied by −2.]
2y = 3 − 4z [Equation B]
Step 2: −2y = 15 − 2z [Equation A in Step 1 is simplified.]
2y = 3 − 4z [Equation B]
Step 3: 0 = 18 − 6z [Equations in Step 2 are added.]
Step 4: 6z = 18
Step 5: z = 3
In which step did the student first make an error?
Step1
Step 2
Step 3
Step 4
anonymous
 one year ago
The work of a student to solve a set of equations is shown: Equation A: y = 15 − 2z Equation B: 2y = 3 − 4z Step 1: −2(y) = −2(15 − 2z) [Equation A is multiplied by −2.] 2y = 3 − 4z [Equation B] Step 2: −2y = 15 − 2z [Equation A in Step 1 is simplified.] 2y = 3 − 4z [Equation B] Step 3: 0 = 18 − 6z [Equations in Step 2 are added.] Step 4: 6z = 18 Step 5: z = 3 In which step did the student first make an error? Step1 Step 2 Step 3 Step 4

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Luigi0210
 one year ago
Best ResponseYou've already chosen the best response.2In step 2 they did not simplify right. They multiplied the 2 to the y but not the entire equation.
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