## anonymous one year ago Help with Algebra 2B? Rationalize the denominator and simplify (wait for the equation in comments):

1. anonymous

$\frac{ 3\sqrt{2}-2\sqrt{3} }{ 3\sqrt{2}+2\sqrt{3} }$

2. anonymous

@Hero

3. Hero

Multiply top and bottom by the conjugate.

4. anonymous

So @Hero it would be $\frac{ (3\sqrt{2}-2\sqrt{3})(3\sqrt{2}-2\sqrt{3}) }{ (3\sqrt{2}+2\sqrt{3})(3\sqrt{2}-2\sqrt{3}) }$ which would simplify to $\frac{ 3\sqrt{2}^{2}+2\sqrt{3}^{2} }{ 3\sqrt{2}^{2}-2\sqrt{3}^{2} }$ am I right so far?

5. Hero

It's more like: $\frac{ (3\sqrt{2}-2\sqrt{3})(3\sqrt{2}-2\sqrt{3}) }{ (3\sqrt{2}+2\sqrt{3})(3\sqrt{2}-2\sqrt{3}) } = \frac{(3\sqrt{2}-2\sqrt{3})^2}{(3\sqrt{2})^2 - (2\sqrt{3})^2}$

6. anonymous

Oh ok thanks that helps a lot I think I can do it from here.