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theopenstudyowl

  • one year ago

I need some help with some Statistics calculator questions! Thankyou!

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  1. theopenstudyowl
    • one year ago
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  2. Michele_Laino
    • one year ago
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    I think it is 28.26 under the label "Coef"

  3. theopenstudyowl
    • one year ago
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    cool!

  4. Michele_Laino
    • one year ago
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    here you have this function: \[y = B + Ax\]

  5. theopenstudyowl
    • one year ago
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    ok

  6. Michele_Laino
    • one year ago
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    I say 28.3, which is the value of y when x=0

  7. theopenstudyowl
    • one year ago
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    ok that make sense!

  8. Michele_Laino
    • one year ago
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    I think y=28.26+0.486*x

  9. theopenstudyowl
    • one year ago
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    ok cool!

  10. Michele_Laino
    • one year ago
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    I think it is the subsequent ratio: \[\Large t = \frac{1}{{0.4865}}\]

  11. KyanTheDoodle
    • one year ago
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    Why is the question post orange if you didn't summon me? This is weird O_O

  12. Michele_Laino
    • one year ago
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    namely the last option

  13. KyanTheDoodle
    • one year ago
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    OOOOOOOOOHHHHH it's probably because of the whole QH thing.

  14. theopenstudyowl
    • one year ago
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    cool

  15. theopenstudyowl
    • one year ago
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    thnxs for explaining!

  16. Michele_Laino
    • one year ago
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    I see from your table that the requested value of p is p=0.168, under the label "p"

  17. Michele_Laino
    • one year ago
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    at first row

  18. theopenstudyowl
    • one year ago
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    ok cool sorry for the late reply

  19. theopenstudyowl
    • one year ago
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    bazinga

  20. Michele_Laino
    • one year ago
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    I think p=0.045 at first row, and last column, or "p" column, second table

  21. theopenstudyowl
    • one year ago
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  22. Michele_Laino
    • one year ago
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    I think that we have to use: 30 -2 = 28 degrree of freedom, since we have two parameters, namelythe constants A and B which appears into this formula: y = Ax+B

  23. Michele_Laino
    • one year ago
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    sorry for my grammar errors

  24. theopenstudyowl
    • one year ago
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  25. Michele_Laino
    • one year ago
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    I think it is 19.96

  26. Michele_Laino
    • one year ago
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    please wait

  27. Michele_Laino
    • one year ago
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    it is 0.2316, since the slope is 0.4865

  28. theopenstudyowl
    • one year ago
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    @Michele_Laino sorry for the lare reply, I am currently doing macro right now, here is ht enext question..

  29. Michele_Laino
    • one year ago
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    using the table of the "erf" function the requested value is: 1.96

  30. theopenstudyowl
    • one year ago
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    ok one more

  31. theopenstudyowl
    • one year ago
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    ty

  32. Michele_Laino
    • one year ago
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    here I use standard deviation = 0.2316 range of interval= 0.2316*1.96= 0.454 so my answer would be: 0.4865 +/- 0.454

  33. Michele_Laino
    • one year ago
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    such answer is not an option of yours!

  34. Michele_Laino
    • one year ago
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    try to ask to another QH

  35. theopenstudyowl
    • one year ago
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    still thinking lol?

  36. Michele_Laino
    • one year ago
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    @dan815 please help

  37. theopenstudyowl
    • one year ago
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    ok, what is your answer?

  38. Michele_Laino
    • one year ago
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    my answer is the first option, nevertheless I'm not able to justify it

  39. theopenstudyowl
    • one year ago
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    MINE 2, just checked my work

  40. theopenstudyowl
    • one year ago
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    @Michele_Laino can u answer some more???

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