Bananas1234
  • Bananas1234
Add the rational expressions:2x-1/(x+3)(x+2) + x-4/x+3
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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Bananas1234
  • Bananas1234
@dan815
Bananas1234
  • Bananas1234
@Nnesha
Bananas1234
  • Bananas1234
@rational

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More answers

Nnesha
  • Nnesha
^gO_Od one ^^^^^
Bananas1234
  • Bananas1234
sorry i dont normally tag people im in a hurry, last day of school for me :)
Nnesha
  • Nnesha
it's okay i'm saying tag rational for rational expressions that was good ! :P alright first step find common denominator
Bananas1234
  • Bananas1234
oh ha ha!!
Bananas1234
  • Bananas1234
well x + 3 is common
Nnesha
  • Nnesha
\[\huge\rm \frac{ ? }{ (x+3)(x+2) }\] yes right (x+3) is common and (x+2) stay there|dw:1433451813766:dw| 2x-1 denominator and common denominator are the same so that's why 2x-1 stay same at the numerator now x-4 ave x+3 at the denominator but not x+2 so multiply (x-4) times (x+3)
Nnesha
  • Nnesha
2x-1** my bad :>.,
Nnesha
  • Nnesha
\[\huge\rm \frac{ (2x-1) +(x-4)(x+2) }{ (x+3)(x+2) }\] like this now solve
Bananas1234
  • Bananas1234
x^2-9/z^2-x-6?
Bananas1234
  • Bananas1234
ps x not z
Bananas1234
  • Bananas1234
oops*
Nnesha
  • Nnesha
yep numerator is right don't distribute denominator
Nnesha
  • Nnesha
\[\huge\rm \frac{ x^2 -9}{ (x+3)(x+2) }\] factor x^2 -9
Nnesha
  • Nnesha
difference of square a^2-b^2 =(a+b)(a-b)
Bananas1234
  • Bananas1234
x-3 for top?
Nnesha
  • Nnesha
not just x-3 x^2-9 = ?
Bananas1234
  • Bananas1234
hmm not sure
Nnesha
  • Nnesha
remember difference of square = answer should be two parentheses (?? + ??? )( ??? - ?? ?)
Bananas1234
  • Bananas1234
(x-3)(x+3)?
Nnesha
  • Nnesha
yes rght
Nnesha
  • Nnesha
right ** >.,
Nnesha
  • Nnesha
\[\huge\rm \frac{ (x+3)(x-3)}{ (x+3)(x+2) } = ?\]
Bananas1234
  • Bananas1234
x-3/x+3?
Nnesha
  • Nnesha
NOPE
Bananas1234
  • Bananas1234
why not?
Nnesha
  • Nnesha
how did you get x-3 and x+3 at the denominator ? what about x+2 and x+3 which is 't the numerator ?
Bananas1234
  • Bananas1234
i guess that would make more sence
Nnesha
  • Nnesha
\[\huge\rm \frac{ (x+3)(x-3)}{ (x+3)(x+2) } = ?\] what's ur next step ?
Nnesha
  • Nnesha
#cancel
Bananas1234
  • Bananas1234
cancel out the x+3's??
Nnesha
  • Nnesha
yes right!
Bananas1234
  • Bananas1234
leaving x - 3 and x+ 2?
Nnesha
  • Nnesha
yes right x-3/x+2
Bananas1234
  • Bananas1234
Thanks

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