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Bananas1234

  • one year ago

Add the rational expressions:2x-1/(x+3)(x+2) + x-4/x+3

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  1. Bananas1234
    • one year ago
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    @dan815

  2. Bananas1234
    • one year ago
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    @Nnesha

  3. Bananas1234
    • one year ago
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    @rational

  4. Nnesha
    • one year ago
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    ^gO_Od one ^^^^^

  5. Bananas1234
    • one year ago
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    sorry i dont normally tag people im in a hurry, last day of school for me :)

  6. Nnesha
    • one year ago
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    it's okay i'm saying tag rational for rational expressions that was good ! :P alright first step find common denominator

  7. Bananas1234
    • one year ago
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    oh ha ha!!

  8. Bananas1234
    • one year ago
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    well x + 3 is common

  9. Nnesha
    • one year ago
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    \[\huge\rm \frac{ ? }{ (x+3)(x+2) }\] yes right (x+3) is common and (x+2) stay there|dw:1433451813766:dw| 2x-1 denominator and common denominator are the same so that's why 2x-1 stay same at the numerator now x-4 ave x+3 at the denominator but not x+2 so multiply (x-4) times (x+3)

  10. Nnesha
    • one year ago
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    2x-1** my bad :>.,

  11. Nnesha
    • one year ago
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    \[\huge\rm \frac{ (2x-1) +(x-4)(x+2) }{ (x+3)(x+2) }\] like this now solve

  12. Bananas1234
    • one year ago
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    x^2-9/z^2-x-6?

  13. Bananas1234
    • one year ago
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    ps x not z

  14. Bananas1234
    • one year ago
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    oops*

  15. Nnesha
    • one year ago
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    yep numerator is right don't distribute denominator

  16. Nnesha
    • one year ago
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    \[\huge\rm \frac{ x^2 -9}{ (x+3)(x+2) }\] factor x^2 -9

  17. Nnesha
    • one year ago
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    difference of square a^2-b^2 =(a+b)(a-b)

  18. Bananas1234
    • one year ago
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    x-3 for top?

  19. Nnesha
    • one year ago
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    not just x-3 x^2-9 = ?

  20. Bananas1234
    • one year ago
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    hmm not sure

  21. Nnesha
    • one year ago
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    remember difference of square = answer should be two parentheses (?? + ??? )( ??? - ?? ?)

  22. Bananas1234
    • one year ago
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    (x-3)(x+3)?

  23. Nnesha
    • one year ago
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    yes rght

  24. Nnesha
    • one year ago
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    right ** >.,

  25. Nnesha
    • one year ago
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    \[\huge\rm \frac{ (x+3)(x-3)}{ (x+3)(x+2) } = ?\]

  26. Bananas1234
    • one year ago
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    x-3/x+3?

  27. Nnesha
    • one year ago
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    NOPE

  28. Bananas1234
    • one year ago
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    why not?

  29. Nnesha
    • one year ago
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    how did you get x-3 and x+3 at the denominator ? what about x+2 and x+3 which is 't the numerator ?

  30. Bananas1234
    • one year ago
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    i guess that would make more sence

  31. Nnesha
    • one year ago
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    \[\huge\rm \frac{ (x+3)(x-3)}{ (x+3)(x+2) } = ?\] what's ur next step ?

  32. Nnesha
    • one year ago
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    #cancel

  33. Bananas1234
    • one year ago
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    cancel out the x+3's??

  34. Nnesha
    • one year ago
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    yes right!

  35. Bananas1234
    • one year ago
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    leaving x - 3 and x+ 2?

  36. Nnesha
    • one year ago
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    yes right x-3/x+2

  37. Bananas1234
    • one year ago
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    Thanks

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