Looking for something else?

Not the answer you are looking for? Search for more explanations.

## More answers

Looking for something else?

Not the answer you are looking for? Search for more explanations.

- anonymous

Please help! I don't understand this. Picture of the graph uploaded below. If 300 people donated blood in Springfield, about how many were AB+? (Note that you must multiply by the percent to find out.)

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this

and **thousands** of other questions.

Get your **free** account and access **expert** answers to this and **thousands** of other questions

- anonymous

- katieb

See more answers at brainly.com

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this

and **thousands** of other questions

- anonymous

- jim_thompson5910

I honestly hate problems like this. They are designed to trip people up because of the wiggle room in the values you read off the graph. It's some percentage less than 5%, but the exact percentage? Who knows really.
What percentage for AB+ did you get?

- anonymous

I mean I figured it had to be somewhere around 1% or 1.5% I can't really tell.

Looking for something else?

Not the answer you are looking for? Search for more explanations.

- jim_thompson5910

The blue bar for AB+ is larger, and beyond the halfway point from 0% to 5%
so I'd say the blue is like 3% maybe?

- jim_thompson5910

but this is an educated guess really

- phi

I would guess about 3%

- jim_thompson5910

the red bar is below halfway, so 1% or so
in total, 1% + 3% = 4% for all of AB+ from both towns

- jim_thompson5910

whatever the percent is, multiply the decimal form of it by 300 to get your answer

- phi

It sounds like they want only Springfield?

- jim_thompson5910

oh right, nvm the other town then

- anonymous

I believe the answer is 9.

- jim_thompson5910

3% of 300 = 9, yes

- anonymous

Ah well, thank you for helping me make sense of it. I'll probably be back with another simple problem that i think is difficult!!

- jim_thompson5910

you're welcome

Looking for something else?

Not the answer you are looking for? Search for more explanations.