I will medal and fan I need help with part 2 Xavier is riding on a Ferris wheel at the local fair. His height can be modeled by the equation H(t) = 20cosine of the quantity 1 over 15 times t + 30, where H represents the height of the person above the ground in feet at t seconds. Part 1: How far above the ground is Xavier before the ride begins? Part 2: How long does the Ferris wheel take to make one complete revolution? Part 3: Assuming Xavier begins the ride at the top, how far from the ground is the edge of the Ferris wheel, when Xavier's height above the ground reaches a minimum?

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

I will medal and fan I need help with part 2 Xavier is riding on a Ferris wheel at the local fair. His height can be modeled by the equation H(t) = 20cosine of the quantity 1 over 15 times t + 30, where H represents the height of the person above the ground in feet at t seconds. Part 1: How far above the ground is Xavier before the ride begins? Part 2: How long does the Ferris wheel take to make one complete revolution? Part 3: Assuming Xavier begins the ride at the top, how far from the ground is the edge of the Ferris wheel, when Xavier's height above the ground reaches a minimum?

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

So the H(t) function is this \[\Large H(t) = 20\cos\left(\frac{1}{15}t+30\right)\] right?
Yea solved it and got 50. Is that correct?

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

so the +30 is definitely inside the parenthesis and not outside?
\[H(t)=20 \cos \left( \frac{ π }{ 15 }t \right)+30\] that's the equation
oh ok
So yes, plugging in t = 0 gives 50 as the output
at t = 0 seconds, he is at a height of 50 ft
Okay, what exactly do I do for the second part? That part confuses me
The part in red represents the coefficient for the t variable \[\Large H(t)=20 \cos \left( {\color{red}{\frac{ π }{ 15 }}}t \right)+30\] this is the value of B. To find the period you would use the formula T = 2pi/B
So it would be \[\frac{ 2π }{ \left( \frac{ π }{ 15 } \right) }\]
yes, simplify that fraction
We can take out the pi's right? so we would now have \[\frac{ 2 }{ 15 }\]
\[\large \frac{ 2π }{ \left( \frac{ π }{ 15 } \right) } = \frac{2\pi}{1} \times \frac{15}{\pi} = ???\]
Ohh \[\frac{ 30π }{ 1π }\] ?
and the pi's will cancel
so T = 30 is the period t is in seconds, which means the period is 30 seconds that means the ferris wheel completes a cycle every 30 seconds
Okay thank you :) I'll try and see if I can get part three on my own and if not I'll let you know :)
alright
Okay I'm confused as to what the question is asking exactly
|dw:1433458814224:dw|
"Part 3: Assuming Xavier begins the ride at the top, how far from the ground is the edge of the Ferris wheel, when Xavier's height above the ground reaches a minimum?" at time t = 0, he starts at this point here |dw:1433458873515:dw|
how long does it take to go around the full circle?
30 seconds
so how long does it take to go from the very top, to the very bottom?
15 seconds
plug in t = 15 and tell me what you get
I get a decimal when I plug it into my calculator 92.83185307
make sure you are in radian mode
\[H(15)=20\left( \frac{ π }{ 15 }15 \right)+30\] \[\frac{ π }{ 15 }\times \frac{ 15 }{ 1 }=\frac{ 15 }{ 15 }=1\] \[20\left( 1 \right)+30=50\] correct?
Wait
\[H(15)=20\left( \frac{ π }{ 15 }15 \right)+30 \] \[\frac{ π }{ 15 }\times \frac{ 15 }{ 1 }=\frac{ 15π }{ 15 }=1π?\]
so you'll have 20*cos(pi) + 30 = ???
I get 49.9?
you should find cos(pi) = -1 try again
10?
yep 10
Okay so the edge of the Farris wheel is 10ft from the ground when Xavier's height above the ground reaches a minimum
yep the lowest it goes is 10 ft off the ground |dw:1433460789409:dw|
Thank you :)
you're welcome

Not the answer you are looking for?

Search for more explanations.

Ask your own question