anonymous
  • anonymous
I will medal and fan I need help with part 2 Xavier is riding on a Ferris wheel at the local fair. His height can be modeled by the equation H(t) = 20cosine of the quantity 1 over 15 times t + 30, where H represents the height of the person above the ground in feet at t seconds. Part 1: How far above the ground is Xavier before the ride begins? Part 2: How long does the Ferris wheel take to make one complete revolution? Part 3: Assuming Xavier begins the ride at the top, how far from the ground is the edge of the Ferris wheel, when Xavier's height above the ground reaches a minimum?
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
@jim_thompson5910 ?
jim_thompson5910
  • jim_thompson5910
So the H(t) function is this \[\Large H(t) = 20\cos\left(\frac{1}{15}t+30\right)\] right?
anonymous
  • anonymous
Yea solved it and got 50. Is that correct?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

jim_thompson5910
  • jim_thompson5910
so the +30 is definitely inside the parenthesis and not outside?
anonymous
  • anonymous
\[H(t)=20 \cos \left( \frac{ π }{ 15 }t \right)+30\] that's the equation
jim_thompson5910
  • jim_thompson5910
oh ok
jim_thompson5910
  • jim_thompson5910
So yes, plugging in t = 0 gives 50 as the output
jim_thompson5910
  • jim_thompson5910
at t = 0 seconds, he is at a height of 50 ft
anonymous
  • anonymous
Okay, what exactly do I do for the second part? That part confuses me
jim_thompson5910
  • jim_thompson5910
The part in red represents the coefficient for the t variable \[\Large H(t)=20 \cos \left( {\color{red}{\frac{ π }{ 15 }}}t \right)+30\] this is the value of B. To find the period you would use the formula T = 2pi/B
anonymous
  • anonymous
So it would be \[\frac{ 2π }{ \left( \frac{ π }{ 15 } \right) }\]
jim_thompson5910
  • jim_thompson5910
yes, simplify that fraction
anonymous
  • anonymous
We can take out the pi's right? so we would now have \[\frac{ 2 }{ 15 }\]
jim_thompson5910
  • jim_thompson5910
\[\large \frac{ 2π }{ \left( \frac{ π }{ 15 } \right) } = \frac{2\pi}{1} \times \frac{15}{\pi} = ???\]
anonymous
  • anonymous
Ohh \[\frac{ 30π }{ 1π }\] ?
jim_thompson5910
  • jim_thompson5910
and the pi's will cancel
jim_thompson5910
  • jim_thompson5910
so T = 30 is the period t is in seconds, which means the period is 30 seconds that means the ferris wheel completes a cycle every 30 seconds
anonymous
  • anonymous
Okay thank you :) I'll try and see if I can get part three on my own and if not I'll let you know :)
jim_thompson5910
  • jim_thompson5910
alright
anonymous
  • anonymous
Okay I'm confused as to what the question is asking exactly
jim_thompson5910
  • jim_thompson5910
|dw:1433458814224:dw|
jim_thompson5910
  • jim_thompson5910
"Part 3: Assuming Xavier begins the ride at the top, how far from the ground is the edge of the Ferris wheel, when Xavier's height above the ground reaches a minimum?" at time t = 0, he starts at this point here |dw:1433458873515:dw|
jim_thompson5910
  • jim_thompson5910
how long does it take to go around the full circle?
anonymous
  • anonymous
30 seconds
jim_thompson5910
  • jim_thompson5910
so how long does it take to go from the very top, to the very bottom?
anonymous
  • anonymous
15 seconds
jim_thompson5910
  • jim_thompson5910
plug in t = 15 and tell me what you get
anonymous
  • anonymous
I get a decimal when I plug it into my calculator 92.83185307
jim_thompson5910
  • jim_thompson5910
make sure you are in radian mode
anonymous
  • anonymous
\[H(15)=20\left( \frac{ π }{ 15 }15 \right)+30\] \[\frac{ π }{ 15 }\times \frac{ 15 }{ 1 }=\frac{ 15 }{ 15 }=1\] \[20\left( 1 \right)+30=50\] correct?
anonymous
  • anonymous
Wait
anonymous
  • anonymous
\[H(15)=20\left( \frac{ π }{ 15 }15 \right)+30 \] \[\frac{ π }{ 15 }\times \frac{ 15 }{ 1 }=\frac{ 15π }{ 15 }=1π?\]
jim_thompson5910
  • jim_thompson5910
so you'll have 20*cos(pi) + 30 = ???
anonymous
  • anonymous
I get 49.9?
jim_thompson5910
  • jim_thompson5910
you should find cos(pi) = -1 try again
anonymous
  • anonymous
10?
jim_thompson5910
  • jim_thompson5910
yep 10
anonymous
  • anonymous
Okay so the edge of the Farris wheel is 10ft from the ground when Xavier's height above the ground reaches a minimum
jim_thompson5910
  • jim_thompson5910
yep the lowest it goes is 10 ft off the ground |dw:1433460789409:dw|
anonymous
  • anonymous
Thank you :)
jim_thompson5910
  • jim_thompson5910
you're welcome

Looking for something else?

Not the answer you are looking for? Search for more explanations.