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Directions: Drag each condition to the correct location on the table. Classify each condition based on the table headings.

Mathematics
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do you have anything so far?
umm no ive tried to read it again and again but it doesn make any sense for which catagory to put them in ;/
"A right triangle with one leg of 6 inches and area 24 square inches" what must the height be?
3 ? because 6 x 3 = 24
6 times 3 isn't 24
oh 18 :/ i dont know where my brain is today
i meant 6 x 4
6 times 4 = 24 works if you have a rectangle that is 6 by 4
but with triangles, you cut that in half to get the area area of triangle = (base*height)/2
so 6 x 4 = 24 / 2? = 12
but we want the area to be 24, not 12
-3- hmm
|dw:1433454993132:dw|
how can we fix it? what must 4 be changed into?
2?
|dw:1433455132539:dw|
hmm seems like the area got smaller when we wanted it to get bigger
so 6 x 6
6 times 6 = 36 cut that in half: 36/2 = 18 remember we want an area of 24
but i dont know how to get there
solve for h (6*h)/2 = 24
whats the hieght
(6*h)/2 = 24 6*h = 24*2 6*h = 48 h = ???
um so 6 x4=24 6x 8 - 48
yeah the height must be 8
it cannot be anything else, which means only 1 triangle is possible
oki
but there are more boxes
Well, thanks for your help. :)
ok let's go over the other boxes
"A scalene triangle with whole number side lengths and perimeter 6 inches" what possible triangles can you think of here?
no angles
you sure? no triangles possible?
ya cuz scalene is no sides 0
scalene just means all 3 sides are different
what 3 whole numbers add up to 6?
18
re-read my question
i dont know 2?
2 and what else
2 + _____ + ______ = 6
3 and 1
yes
it turns out this is the only way to add up 3 different whole numbers to get 6
:/
what's wrong?
where are you stuck?
i dont even know...i feel like i cant even do this problem A) its logged me out of the question and has a new question :/ and B) i just....so hard :'(
well take a break from it. I'd be frustrated too at tech like that
ya k
Thanks though

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