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\\[\int\limits_{}^{} \frac{ 7x-11 }{ x^2-10x+41 }\]

Is this your integral?\[\Large \int\limits_{}^{}\frac{ 7x-11 }{ x^2-10x+41 }\]

yes. that is correct.

You have to do what is called a u-substitution for this

I think I follow.

So I can add and subtract 24 to the numerator right?

since it's like adding 0

Sorry that got cut off

I'm still kinda confused about where I got from here. Sorry.

Yes.

Oh! Now that makes sense.

Yeah I've seen it before.

So to get 1 in the numerator i pull out 24.

i haven't done that in forever. I remember doing it a while back though.

Bingo :)

Now it all makes sense. Thank you so much, you've saved me.

You're welcome, glad to help :)