love_to_love_you
  • love_to_love_you
Write an equation for the translation of y = 2/x that has the given asymptotes. x = 4 and y = -8 Show all work
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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love_to_love_you
  • love_to_love_you
@zepdrix
jim_thompson5910
  • jim_thompson5910
what is the vertical asymptote for y = 2/x ?
love_to_love_you
  • love_to_love_you
oh nvm I don't even have to do this problem. Could you help me with something else?

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love_to_love_you
  • love_to_love_you
@jim_thompson5910
jim_thompson5910
  • jim_thompson5910
sure
love_to_love_you
  • love_to_love_you
Okay so what I have to do is explain why for each problem. I have the answers already but I do not know the explanation.
jim_thompson5910
  • jim_thompson5910
ok
love_to_love_you
  • love_to_love_you
a. If sin theta = sqrt 2/2, which could not be the value of theta? 225 degrees
jim_thompson5910
  • jim_thompson5910
where is 225 degrees? which quadrant?
love_to_love_you
  • love_to_love_you
Um is it quadrant 3?
jim_thompson5910
  • jim_thompson5910
yes, and sine is negative in Q3 and Q4
jim_thompson5910
  • jim_thompson5910
so it's impossible for theta to be 225 degrees
love_to_love_you
  • love_to_love_you
ok
love_to_love_you
  • love_to_love_you
b. For which value of theta is tan theta equal to sin theta? 2pi
jim_thompson5910
  • jim_thompson5910
I'm guessing you had a list of choices?
love_to_love_you
  • love_to_love_you
It's a problem. I have 2 problems. They have a and b parts to them
love_to_love_you
  • love_to_love_you
So what we have to do is explain why this is the correct answer/ show work.
jim_thompson5910
  • jim_thompson5910
well tan(theta) is the same as sin(theta)/cos(theta) it's one of the many identities
jim_thompson5910
  • jim_thompson5910
\[\Large \tan(\theta) = \sin(\theta)\] \[\Large \frac{\sin(\theta)}{\cos(\theta)} = \sin(\theta)\] \[\Large \frac{\sin(\theta)}{\cos(\theta)}*{\color{red}{\frac{1}{\sin(\theta)}}} = \sin(\theta)*{\color{red}{\frac{1}{\sin(\theta)}}}\] \[\Large \frac{\cancel{\sin(\theta)}}{\cos(\theta)}*{\color{black}{\frac{1}{\cancel{\sin(\theta)}}}} = \cancel{\sin(\theta)}*{\color{black}{\frac{1}{\cancel{\sin(\theta)}}}}\] \[\Large \frac{1}{\cos(\theta)} = 1\] in step 3, I'm multiplying both sides by 1/sin(theta) since both sides have a sine that cancels making sense so far?
love_to_love_you
  • love_to_love_you
Yeah
love_to_love_you
  • love_to_love_you
so what happens next?
jim_thompson5910
  • jim_thompson5910
multiply both sides by cos(theta) to get cos(theta) = 1 then you'll use arccosine to isolate theta
love_to_love_you
  • love_to_love_you
Idk how to use arccosine very well
jim_thompson5910
  • jim_thompson5910
what kind of calculator do you have?
love_to_love_you
  • love_to_love_you
just an online graphing calc
jim_thompson5910
  • jim_thompson5910
what's the link to it? so I can have a look
love_to_love_you
  • love_to_love_you
it's a download from my school
jim_thompson5910
  • jim_thompson5910
I gotcha
jim_thompson5910
  • jim_thompson5910
ok I'm going to use this calculator here http://web2.0calc.com/
love_to_love_you
  • love_to_love_you
ok
jim_thompson5910
  • jim_thompson5910
click the "rad" button (next to "deg") to convert over to radian mode
jim_thompson5910
  • jim_thompson5910
then type in "arccos(1)" without quotes http://web2.0calc.com/#arccos(1) what do you get?
love_to_love_you
  • love_to_love_you
cos^-1(1) = 0
love_to_love_you
  • love_to_love_you
and then there's a tiny 2 pi under it
love_to_love_you
  • love_to_love_you
@jim_thompson5910
jim_thompson5910
  • jim_thompson5910
correct, so 0 radians is one answer notice how 2pi radians and 0 radians are coterminal angles
jim_thompson5910
  • jim_thompson5910
so since theta = 0 is one answer, theta = 2pi is also an answer there are infinitely many other answers. They only want theta = 2pi for some reason
love_to_love_you
  • love_to_love_you
So that makes 2 pi the answer as well?
jim_thompson5910
  • jim_thompson5910
yeah there are infinitely many answers, but the computer or teacher is only accepting 2pi
love_to_love_you
  • love_to_love_you
ok
love_to_love_you
  • love_to_love_you
I'm gonna try to figure out a for the next problem on my own but can you help me with b?
love_to_love_you
  • love_to_love_you
A man stands on his balcony, 140 feet above the ground. He looks at the ground, with his sight line forming an angle of 75 degrees with the building, and sees a bus stop. The function d = 140 sec theta models the distance from the man to any object given his angle of sight theta. How far is the bus stop from the man? Round your answer. 541 ft.
jim_thompson5910
  • jim_thompson5910
140*sec(theta) = 140*(1/cos(theta)) plug in theta = 75 make sure you are in degree mode use this calculator if needed http://web2.0calc.com/
love_to_love_you
  • love_to_love_you
541
jim_thompson5910
  • jim_thompson5910
yeah I'm getting 540.9184627208766586 which rounds to 541 (assuming you round to the nearest foot)
love_to_love_you
  • love_to_love_you
yeah i rounded
love_to_love_you
  • love_to_love_you
Thanks so much
jim_thompson5910
  • jim_thompson5910
you're welcome

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