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anonymous

  • one year ago

Please help I'm having a lot of trouble here! A student made the table below to show the steps to prove that DC is equal to EC: Statements Justifications DC = EC CPCTC

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  1. anonymous
    • one year ago
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  2. anonymous
    • one year ago
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    @Hero @Kainui

  3. anonymous
    • one year ago
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    @Michele_Laino

  4. Michele_Laino
    • one year ago
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    the missing statement is: \[\Large m\angle ACE = m\angle ACD + m\angle DCE\] for angle addition postulate

  5. anonymous
    • one year ago
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    omg okay thanks so much, now i have to explain why we needed this step

  6. anonymous
    • one year ago
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    cam i say because DBC=Eac?

  7. anonymous
    • one year ago
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    so without it we wouldn't be able to prove this?

  8. Michele_Laino
    • one year ago
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    no, since the condition DBC= EAC is necessary nevertheless it is not suffice

  9. anonymous
    • one year ago
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    Oh, okay

  10. Michele_Laino
    • one year ago
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    my condition is necessary since we have: |dw:1433462306474:dw| then the two triangles are congruent each other

  11. Michele_Laino
    • one year ago
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    using ASA postulate

  12. anonymous
    • one year ago
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    okay, but why would we use the same statement twice? the statement we have now is the same as statement 4

  13. Michele_Laino
    • one year ago
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    you are right! Then we can use directly this statement: \[\Large m\angle BCD = m\angle ACE\] by the transitive property of congruence relation

  14. anonymous
    • one year ago
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    Ohhh! Okay, great! And we would need this step to simplify steps 4-6?

  15. Michele_Laino
    • one year ago
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    yes!

  16. anonymous
    • one year ago
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    yaay! Thanks so much!

  17. Michele_Laino
    • one year ago
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    thanks! :)

  18. anonymous
    • one year ago
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    yw!

  19. Michele_Laino
    • one year ago
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    :)

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