A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 one year ago
is anyone good with Inverse of exponential functions? If so can someone help me with a few questions? I will fan and medal.
anonymous
 one year ago
is anyone good with Inverse of exponential functions? If so can someone help me with a few questions? I will fan and medal.

This Question is Closed

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Given f(x)=3^x, find f^–1(x) and f^–1(27).

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@zepdrix help please?

Kainui
 one year ago
Best ResponseYou've already chosen the best response.0The inverse of an exponential function is a logarithm, they're sorta weird if you're new to them, so here's an example: \[ \log_2(8)\] The little 2 on the log is the base, and this is basically saying, "what power of 2 is this?" So since \(8=2^3\) then we can write: \[ \log_2(8)=3\] so the trick is if we have something like \(y=2^x\) the inverse will be to take the logarithm base 2 of both sides since: \[ \log_2(y) = \log_2(2^x)\] Notice that right side is saying what's the power on \(2^x\) ? Well that's just x! So we rewrite it: \[ \log_2(y) = x\] Since this is the inverse function we switch y and x (or in your case f(x) and x. to get: \[ \log_2(x) = y\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay well that kinda makes sense

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0but can you like sorta walk me through this one? Given f(x)=3^x, find f^–1(x) and f^–1(27). @Kainui

Kainui
 one year ago
Best ResponseYou've already chosen the best response.0Well I walked you through some stuff right there, see if you can take what I'm saying and apply it to solve your problem first and I'll help you.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.