- Bananas1234

What is the least common denominator of the fractions? 7/12m^3n, 3/4mn^2

- schrodinger

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- xapproachesinfinity

what do you see common there?

- Bananas1234

the m's?

- xapproachesinfinity

we have \[\frac{7}{12m^3n},~~~ \frac{1}{4mn^2}\]

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## More answers

- xapproachesinfinity

just for abetter look

- xapproachesinfinity

yah m is common

- xapproachesinfinity

one of them is m^3 and the other just m
so to make it common need to multiply the other by m^2

- Bananas1234

ok

- xapproachesinfinity

top and bottom though

- xapproachesinfinity

what else do you spot is common

- xapproachesinfinity

keep track of what we are doing ok

- Bananas1234

the n's?

- xapproachesinfinity

n is common too right
so we need to multiply left one n top and bottom so we get n^2 for both fractions

- xapproachesinfinity

yes that's right

- xapproachesinfinity

what about 12 and 4
the common multiple is 12 right (least common multiple)

- xapproachesinfinity

so we need to multiply the right fraction by 3 top and bottom

- Bananas1234

yes

- xapproachesinfinity

are you doing what I'm saying

- xapproachesinfinity

'cause i asked you to keep track of what we are doing

- xapproachesinfinity

so now we should have our common denominator ready

- xapproachesinfinity

can you tell me what it is ?

- Bananas1234

ok, idk if i did this right 16m^3n^2

- xapproachesinfinity

hmm 16 should be 12 only

- xapproachesinfinity

other than that it is good

- Bananas1234

ok

- Bananas1234

whats next?

- xapproachesinfinity

hmm you are asked to find common denominator no?
that's all
that is the least common deno

- Bananas1234

Awesome! that was kinda easy! thanks!

- xapproachesinfinity

for a moment i thought you were not convinced haha

- Bananas1234

ha ha no i just thought it was more complicated than that :D

- Bananas1234

Also i checked and the last one that was kinda puzzling was correct.

- xapproachesinfinity

well it was not apparent :)

- Bananas1234

yeah

- xapproachesinfinity

darn the website is slow lol

- Bananas1234

i ageee

- xapproachesinfinity

no my reply was to your last question not the previous one

- xapproachesinfinity

you mean the answer a was the correct

- Bananas1234

yes

- xapproachesinfinity

hmm well the way it is set it might be correct but speaking in mathematics
it is not

- Bananas1234

true

- xapproachesinfinity

are a high school student

- xapproachesinfinity

you*

- Bananas1234

no, middle

- xapproachesinfinity

hmm i see, when you take more math courses you will why we are saying that's wrong

- xapproachesinfinity

but just tell your teacher!

- Bananas1234

ok i will

- Bananas1234

Thanks

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