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So there is 3 different types of crust 7 different types of toppings and 3 different types of cheeses. my favorite pizza would be the stuffed cheese crust with red peppers and mozzarella. what is the probability someone would order my pizza at random?
okay it would be 1/63 because 7x3x3=63 and you choose 1 so it would be 1/63
so that also means there is 63 different choices of pizza?
yes there is 63 different choices. Since your favorite is 1 that means the probability is 1/63
but my favorite includes 1 crust 1 topping and 1 cheese from the choices given?
does that still mean its 1?
Wait are you in connections academy?
I did this project before. I remember having to choose 3 toppings 1 cheese and 1 crust
are the instructions this Imagine you are the owner of a pizza shop that offers three different types of crusts, seven different toppings and three different cheeses. Create an advertisement for your shop with three lists: one for crusts, another for toppings, and a third for cheeses. In your advertisement, emphasize a special where any three-topping pizza with one type of cheese and one type of crust costs only $9.99. Complete this statement and include it on your advertisement: “For this special, we offer ________ different pizza choices for you to choose from!”
yes! lol except that we have 3 different crust 7 different toppings and 3 different cheeses
actually its the same thing
okay so you have to pick 3 toppings 1 cheese and 1 crust if you have the same instructions
well the only thing i need help on is when it asks what is the probability that a person would order your favorite pizza at random?
the probability would stay the same since there is 63 possible combinations and your favorite would be 1 out of 63. So it should be 1/63 still
thanks soo much!