At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
The magnitudes and directions of two forces acting at a point p are given. Approximate the magnitude and direction of the resultant vector, accurate to two decimal places a) 5.00lb, 200 degrees b) 7.00lb, 65 degrees.
find the component
form of each vector
then you can add up the vectors component-wise
x = r*cos(theta) y = r*sin(theta)
Where do I derive the r from?
r = distance from origin to vector tip r = magnitude of vector (ie force applied)
so 5 for part a a) would be 5cos(200) 5sin(200) ?
a = <-4.698,-1.710>
and when I add those up I get = <-1.74,4.63>
they want it "accurate to two decimal places"
...that's what I did o.0
oh, I didn't do a and b accurate to two decimal places but that's because that's part of the process to get to the final answer and should be more accurate I think (hence more decimal places) but the final answer is ok, yeah?
hmm maybe they just want the final answer to 2 decimal places, the steps just leave it to 15 or so (let the calculator handle it)
haha k. final answer looks good though? :)
yes it looks perfect. I'm getting the same
they don't want the
form of the resultant
they want the "magnitude and direction of the resultant vector"
r = magnitude theta = direction r = sqrt(x^2 + y^2) theta = arctan(y/x) will give you the angle, but it will say some angle in Q4. Add on 180 degrees to move the angle to Q2
= <-1.74,4.63> is in Q2
so magnitude: 4.95
theta = 110.58
nvm, my drawing is way off and not to scale
the "7 lb" vector should be longer, that's probably why
It's all good.
I'm getting roughly the same theta
haha yeah just a little disproportional xD
have you been rounding? I have been using calculator storages
I got 110.581677969387
yep yep :) same.
So final answer is The magnitude : 4.95 The direction = 110.58
Fantastic! I like this question better than the car one heh
yeah much easier