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The magnitudes and directions of two forces acting at a point p are given. Approximate the magnitude and direction of the resultant vector, accurate to two decimal places a) 5.00lb, 200 degrees b) 7.00lb, 65 degrees.
@jim_thompson5910 :P can we do this one?
find the component
form of each vector
then you can add up the vectors component-wise
x = r*cos(theta) y = r*sin(theta)
Where do I derive the r from?
r = distance from origin to vector tip r = magnitude of vector (ie force applied)
so 5 for part a a) would be 5cos(200) 5sin(200) ?
a = <-4.698,-1.710>
and when I add those up I get = <-1.74,4.63>
they want it "accurate to two decimal places"
...that's what I did o.0
oh, I didn't do a and b accurate to two decimal places but that's because that's part of the process to get to the final answer and should be more accurate I think (hence more decimal places) but the final answer is ok, yeah?
hmm maybe they just want the final answer to 2 decimal places, the steps just leave it to 15 or so (let the calculator handle it)
haha k. final answer looks good though? :)
yes it looks perfect. I'm getting the same
they don't want the
form of the resultant
they want the "magnitude and direction of the resultant vector"
r = magnitude theta = direction r = sqrt(x^2 + y^2) theta = arctan(y/x) will give you the angle, but it will say some angle in Q4. Add on 180 degrees to move the angle to Q2
= <-1.74,4.63> is in Q2
so magnitude: 4.95
theta = 110.58
nvm, my drawing is way off and not to scale
the "7 lb" vector should be longer, that's probably why
It's all good.
I'm getting roughly the same theta
haha yeah just a little disproportional xD
have you been rounding? I have been using calculator storages
I got 110.581677969387
yep yep :) same.
So final answer is The magnitude : 4.95 The direction = 110.58
Fantastic! I like this question better than the car one heh
yeah much easier