anonymous
  • anonymous
Thanks for helping! 6. Prove the identity: (cosx+cosy)^2+(sinx-siny)^2=2+2cos(x+y) Part I: Complete the left-hand column of the table below following the steps indicated in the right-hand column. (12 points) Given on the left side of the original problem (cosx+cosy)^2+(sinx-siny)^2 Expand each squared term Simplify the expression Apply the Pythagorean identity Apply the addition formula for cosine
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
@dan815 @Kainui @jim_thompson5910 @zepdrix
dan815
  • dan815
expand left side
dan815
  • dan815
(cosx+cosy)^2+(sinx-siny)^2=??

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anonymous
  • anonymous
2+2cos(x+y)
dan815
  • dan815
no i mean expand it
anonymous
  • anonymous
oh gotcha
dan815
  • dan815
and use the cos trig identities
dan815
  • dan815
cosxcosy+sinxsiny = cos(x+y) ?
anonymous
  • anonymous
cos^2(x)+2cos(x)cos(y)-2sin(x)sin(x)+cos^2(x)+sin^2(y)+sin^2
anonymous
  • anonymous
That is the identity?
dan815
  • dan815
i dunno maybe its a negative inbetween
dan815
  • dan815
cosxcosy- sinxsiny = cos(x+y) ?
dan815
  • dan815
http://prntscr.com/7daa8n
dan815
  • dan815
check it out
anonymous
  • anonymous
thanks, from here I can simplify and use the Pythagorean identity?
dan815
  • dan815
yep
dan815
  • dan815
sin^2(a) + cos^2(a) = 1;
dan815
  • dan815
|dw:1433472978378:dw|
dan815
  • dan815
as seen from the unit circle
anonymous
  • anonymous
thanks!
anonymous
  • anonymous
I'll give you a medal. That helped a lot!
anonymous
  • anonymous
I'm new to this site, so I think that is what I'm supposed to do. Ha ha
dan815
  • dan815
okay :)
dan815
  • dan815
you're welcome
anonymous
  • anonymous
:D

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