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AmTran_Bus

  • one year ago

Another integral

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  1. AmTran_Bus
    • one year ago
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    |dw:1433472373374:dw|

  2. AmTran_Bus
    • one year ago
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    I think you can pull it out since it is just a number. Maybe I do need help with the rest.

  3. zepdrix
    • one year ago
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    ya looks good :)

  4. zepdrix
    • one year ago
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    \[\Large\rm \int\limits 1 dx=?\]

  5. AmTran_Bus
    • one year ago
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    Right.

  6. AmTran_Bus
    • one year ago
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    x

  7. AmTran_Bus
    • one year ago
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    well, plus c

  8. zepdrix
    • one year ago
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    so (ex) evaluated from -5 to 5? ya sounds good :D

  9. AmTran_Bus
    • one year ago
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    Well, this is bad, but can you show me? See, its been a year since clac 1.

  10. AmTran_Bus
    • one year ago
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    e(-5-5)?

  11. AmTran_Bus
    • one year ago
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    Or is it e(5--5)

  12. zepdrix
    • one year ago
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    \[\Large\rm \int\limits e dx=e \color{orangered}{\int\limits dx}=e\color{orangered}{x}\] \[\Large\rm e(x)|_{-5}^5=e(5-(-5))\]Ya the second one looks better.

  13. AmTran_Bus
    • one year ago
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    Thanks again. Just working practice problems till I get sick.

  14. zepdrix
    • one year ago
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    ah good idea :)

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spraguer (Moderator)
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is replying to Can someone tell me what button the professor is hitting...

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