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Babynini
 one year ago
Writing equations for parabolas
Babynini
 one year ago
Writing equations for parabolas

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Babynini
 one year ago
Best ResponseYou've already chosen the best response.0Write eq in standard form of the parabola that satisfies f= (4,3) directix x=1

Babynini
 one year ago
Best ResponseYou've already chosen the best response.0so vertex would be = (1.5,3) ?

Babynini
 one year ago
Best ResponseYou've already chosen the best response.0@jim_thompson5910 haha sorry for bugging you all day!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1433483905158:dw

Babynini
 one year ago
Best ResponseYou've already chosen the best response.0A faster way to do it is realize that we can pick a point on the directrix say d = (1,3) and the f = (4,3) and then find the middle distance from 1 to 4 which is 1.5 so the v = (1.5,3)

Babynini
 one year ago
Best ResponseYou've already chosen the best response.0I just need to write the equation now. Which i'm not sure how to do D:

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.0mmm vertex looks good :)

Babynini
 one year ago
Best ResponseYou've already chosen the best response.0it's horizontal so: 4p(xh)=(yk)^2 4p(x1.5)=(y3)^2 ?

Babynini
 one year ago
Best ResponseYou've already chosen the best response.0oh! p is the distance is from vertex to foci?

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.0distance between focus and directrix was 5, ya? p is half of that. the value you used to find the vertex. yes.

Babynini
 one year ago
Best ResponseYou've already chosen the best response.04(2.5)(x1.5)=(y3)^2

Babynini
 one year ago
Best ResponseYou've already chosen the best response.0how would I write that more attractively :P

Babynini
 one year ago
Best ResponseYou've already chosen the best response.0is it ok to write it as y^2=10x18 ?

Babynini
 one year ago
Best ResponseYou've already chosen the best response.0or should I write it as y= +/ sqroot 10x+18 ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[(x+1)^2=(x4)2+(y3)^2\] \[x^2+2x+1=x^28x+16+(y3)^2\] \[x^2+2x+1x^2+8x16=(y3)^2\] \[(y3)^2=10x15\]

Babynini
 one year ago
Best ResponseYou've already chosen the best response.0@surjithayer we forgot the shift upwards. o.0

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.0shift upwards? what? 0_o

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.0That's what the y3 is, ya?

Babynini
 one year ago
Best ResponseYou've already chosen the best response.0the focal point is (4,3) so we know that it's not on the x = 0 line

Babynini
 one year ago
Best ResponseYou've already chosen the best response.0but when I put the equation into a graphing thing it puts it on the x line

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.0it does? 0_o https://www.desmos.com/calculator/wyivsbib3n looks ok to me.

Babynini
 one year ago
Best ResponseYou've already chosen the best response.0hrrm I simplified it further and it was coming out wrong. Probably my calculations were wrong. Ok, all good. Thanks :)
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