Equation for lower half of parabola.

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Equation for lower half of parabola.

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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Find an eq for the lower half of the parabola, without restriction. (y-5)^2 = 4x-2
it says for the lower half
It's a parabola opening to the RIGHT, ya? So if you drew it, you would see that it `fails the vertical line test`. We want to show that either branch of the parabola IS a function. So we'll end up with y=(plus/minus) squareroot(x stuff) and to get the LOWER Half of the parabola, we want the negative of that root.

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Do you understand how to get it into the form y=stuff from what they've given you? :)
em i'm trying but i'm getting it wrong.
You ... you and your ways miriam -_- ok let's see where we're going wrong,\[\Large\rm (y-5)^2 = 4x-2\]
square root as first step, ya?
\[\Large\rm y-5=\pm\sqrt{4x-2}\]Add some 5 business in there,\[\Large\rm y=\pm\sqrt{4x-2}+5\]
We want the lower branch, ya? So we only want the negative root,\[\Large\rm y=-\sqrt{4x-2}+5\]
I was simplifying first and that was making it come out wrong
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woops i buried the wrong solution in the picture -_- hehe
Oh simplifying? i see
aww lightbulbs stil haha
it's ok, it's fabulous ;D
heh :3

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