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Babynini

  • one year ago

Equation for lower half of parabola.

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  1. Babynini
    • one year ago
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    Find an eq for the lower half of the parabola, without restriction. (y-5)^2 = 4x-2

  2. hwyl
    • one year ago
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    it says for the lower half

  3. zepdrix
    • one year ago
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    It's a parabola opening to the RIGHT, ya? So if you drew it, you would see that it `fails the vertical line test`. We want to show that either branch of the parabola IS a function. So we'll end up with y=(plus/minus) squareroot(x stuff) and to get the LOWER Half of the parabola, we want the negative of that root.

  4. zepdrix
    • one year ago
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    Do you understand how to get it into the form y=stuff from what they've given you? :)

  5. Babynini
    • one year ago
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    em i'm trying but i'm getting it wrong.

  6. zepdrix
    • one year ago
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    You ... you and your ways miriam -_- ok let's see where we're going wrong,\[\Large\rm (y-5)^2 = 4x-2\]

  7. zepdrix
    • one year ago
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    square root as first step, ya?

  8. zepdrix
    • one year ago
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    \[\Large\rm y-5=\pm\sqrt{4x-2}\]Add some 5 business in there,\[\Large\rm y=\pm\sqrt{4x-2}+5\]

  9. zepdrix
    • one year ago
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    We want the lower branch, ya? So we only want the negative root,\[\Large\rm y=-\sqrt{4x-2}+5\]

  10. Babynini
    • one year ago
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    I was simplifying first and that was making it come out wrong

  11. zepdrix
    • one year ago
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    |dw:1433476275143:dw|

  12. zepdrix
    • one year ago
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    woops i buried the wrong solution in the picture -_- hehe

  13. zepdrix
    • one year ago
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    Oh simplifying? i see

  14. Babynini
    • one year ago
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    aww lightbulbs stil haha

  15. Babynini
    • one year ago
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    it's ok, it's fabulous ;D

  16. zepdrix
    • one year ago
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    heh :3

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