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anonymous
 one year ago
@UsukiDoll
anonymous
 one year ago
@UsukiDoll

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UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0ok can you hold a minute I'm answering another question

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0so GCF is the greatest common factor.. what doe the equation have in common

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0so what does the equation \[6y^2+12xy^2 \] have in common? hint: there's a variable and a number in common

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0they both have 6 and Y^2

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0so when there is something in common we can place that common part to the side.. so 6y^2 ( whatever there is left)

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0so since a 1 and 2x is left behind we have 6y^2(1+2x) we can check easily by distributing them back 6y^2+12xy^2

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0for #11.. there is only a number in common because there are 2 terms with a variable but the last one is just a number

anonymous
 one year ago
Best ResponseYou've already chosen the best response.03 is a common factor

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0so 3 is on the side and what do we have left ( ) ?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0no because originally we have 3 terms.. B only has two terms.

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0there's a way to make this a bit faster... since 3 is the common factor we just divide 12/3 18/3 and 3/3

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0for twelve, i have to right the answer out.

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0hmm there is just a number is common.. it's similar to the previous problem

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0so what number can be used to divide 3, 9, and 27 ?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0wow you're picking this up fast that's right \[3(x^23x+9) \rightarrow 3x^29x+27\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0just a quick guess :/

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0but I have to do the +C C

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0hmmm that would mean that x^2+9x+8 is factorable

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0so there's more than just factoring out the 2 .... SOOO FAST! :D

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0we need long division for this xD

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what does that mean?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I don't understand :/

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0I'm getting burned out.. it's like .. oh mai brain T_T

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0lol geeeeez louiseeee

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0wait. see now I'm not thinking right... we just use factoring and take out the like terms

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0the choices gave me a hint... if it was long division the answer would look different.. ok I can do this now xD!

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0for the first problem, there is a perfect square binomial

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yay we are back on the road lol and okay.

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0so x^216... that's a perfect square in the form of (x^2y^2) = (x+y)(xy)... so what is the square root of 16?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0yes so we have (x+4)(x4) in the denominator.

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0I think we got lucky on the numerator part of this since we need to find a combination of numbers that can produce an 8 and a 16 4 x 4 = 16 4+4 is also 8 and since the pattern is all plus signs, our end result should be something like (x+4)(x+4) and wow it is A

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0because there is at least one pair of x+4 (both in numerator and denominator) in common so that gets cancelled.

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0numerator is that there is one number in common denominator is that it can be split up since 12 is 6 x 2 = 12 and 62 = 4 the problem is should the 2 be negative or the 6 be negative in order to achieve the result of x^2+4x12

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0yes an for the numerator?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0yes 5 is common 5(x2)/ (x+6)(x2) who gets canceled out?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0yes so the answer is 5/(x+6)

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0I have to go for a bit... xD need a break xD!

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0I have to go eat dinner. I'll be back
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