lisa2345
  • lisa2345
@UsukiDoll
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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UsukiDoll
  • UsukiDoll
hiiiii
lisa2345
  • lisa2345
hey :D
lisa2345
  • lisa2345
okay first question

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lisa2345
  • lisa2345
1 Attachment
lisa2345
  • lisa2345
heres the first 3
UsukiDoll
  • UsukiDoll
ok can you hold a minute I'm answering another question
lisa2345
  • lisa2345
yes I can
UsukiDoll
  • UsukiDoll
k back
UsukiDoll
  • UsukiDoll
so GCF is the greatest common factor.. what doe the equation have in common
UsukiDoll
  • UsukiDoll
so what does the equation \[6y^2+12xy^2 \] have in common? hint: there's a variable and a number in common
lisa2345
  • lisa2345
umm this is for 10?
UsukiDoll
  • UsukiDoll
yes
lisa2345
  • lisa2345
they both have 6 and Y^2
UsukiDoll
  • UsukiDoll
yes they do
UsukiDoll
  • UsukiDoll
so when there is something in common we can place that common part to the side.. so 6y^2 ( whatever there is left)
UsukiDoll
  • UsukiDoll
so since a 1 and 2x is left behind we have 6y^2(1+2x) we can check easily by distributing them back 6y^2+12xy^2
lisa2345
  • lisa2345
so it A?
UsukiDoll
  • UsukiDoll
yes
UsukiDoll
  • UsukiDoll
for #11.. there is only a number in common because there are 2 terms with a variable but the last one is just a number
lisa2345
  • lisa2345
3 is a common factor
UsukiDoll
  • UsukiDoll
yes :D
UsukiDoll
  • UsukiDoll
so 3 is on the side and what do we have left ( ) ?
lisa2345
  • lisa2345
its B?
UsukiDoll
  • UsukiDoll
no because originally we have 3 terms.. B only has two terms.
UsukiDoll
  • UsukiDoll
there's a way to make this a bit faster... since 3 is the common factor we just divide 12/3 18/3 and 3/3
lisa2345
  • lisa2345
Got you.. so its D?
UsukiDoll
  • UsukiDoll
yes
lisa2345
  • lisa2345
for twelve, i have to right the answer out.
UsukiDoll
  • UsukiDoll
hmm there is just a number is common.. it's similar to the previous problem
lisa2345
  • lisa2345
okay.
UsukiDoll
  • UsukiDoll
so what number can be used to divide 3, 9, and 27 ?
lisa2345
  • lisa2345
3
lisa2345
  • lisa2345
is my answer ...
lisa2345
  • lisa2345
3(x2-3x+9) ?
UsukiDoll
  • UsukiDoll
wow you're picking this up fast that's right \[3(x^2-3x+9) \rightarrow 3x^2-9x+27\]
lisa2345
  • lisa2345
okay next 3
lisa2345
  • lisa2345
1 Attachment
lisa2345
  • lisa2345
is 13 d?
lisa2345
  • lisa2345
just a quick guess :/
lisa2345
  • lisa2345
wait no I mean b
UsukiDoll
  • UsukiDoll
yes it is B for 13
lisa2345
  • lisa2345
14 b also?
UsukiDoll
  • UsukiDoll
yes
lisa2345
  • lisa2345
okay 15 now
lisa2345
  • lisa2345
2 is common
UsukiDoll
  • UsukiDoll
yes 2 is common
lisa2345
  • lisa2345
2(x2+9x+8)
UsukiDoll
  • UsukiDoll
correct
lisa2345
  • lisa2345
but I have to do the +C -C
UsukiDoll
  • UsukiDoll
hmmm that would mean that x^2+9x+8 is factorable
lisa2345
  • lisa2345
2(x+8)(x+1)
UsukiDoll
  • UsukiDoll
so there's more than just factoring out the 2 .... SOOO FAST! :D
lisa2345
  • lisa2345
did I get it right?
UsukiDoll
  • UsukiDoll
yeah
lisa2345
  • lisa2345
yay! next 3
lisa2345
  • lisa2345
well 2 lol
lisa2345
  • lisa2345
1 Attachment
UsukiDoll
  • UsukiDoll
we need long division for this xD
lisa2345
  • lisa2345
what does that mean?
lisa2345
  • lisa2345
I don't understand :/
UsukiDoll
  • UsukiDoll
I'm getting burned out.. it's like .. oh mai brain T_T
lisa2345
  • lisa2345
lol geeeeez louiseeee
UsukiDoll
  • UsukiDoll
wait. see now I'm not thinking right... we just use factoring and take out the like terms
UsukiDoll
  • UsukiDoll
the choices gave me a hint... if it was long division the answer would look different.. ok I can do this now xD!
UsukiDoll
  • UsukiDoll
for the first problem, there is a perfect square binomial
lisa2345
  • lisa2345
Yay we are back on the road lol and okay.
UsukiDoll
  • UsukiDoll
so x^2-16... that's a perfect square in the form of (x^2-y^2) = (x+y)(x-y)... so what is the square root of 16?
lisa2345
  • lisa2345
4?
UsukiDoll
  • UsukiDoll
yes so we have (x+4)(x-4) in the denominator.
lisa2345
  • lisa2345
that makes it A?
UsukiDoll
  • UsukiDoll
I think we got lucky on the numerator part of this since we need to find a combination of numbers that can produce an 8 and a 16 4 x 4 = 16 4+4 is also 8 and since the pattern is all plus signs, our end result should be something like (x+4)(x+4) and wow it is A
UsukiDoll
  • UsukiDoll
because there is at least one pair of x+4 (both in numerator and denominator) in common so that gets cancelled.
lisa2345
  • lisa2345
okay 17 now
UsukiDoll
  • UsukiDoll
numerator is that there is one number in common denominator is that it can be split up since 12 is 6 x 2 = 12 and 6-2 = 4 the problem is should the 2 be negative or the 6 be negative in order to achieve the result of x^2+4x-12
lisa2345
  • lisa2345
(x+6)(x-2)
UsukiDoll
  • UsukiDoll
yes an for the numerator?
lisa2345
  • lisa2345
5
UsukiDoll
  • UsukiDoll
yes 5 is common 5(x-2)/ (x+6)(x-2) who gets canceled out?
lisa2345
  • lisa2345
(x-2)
UsukiDoll
  • UsukiDoll
yes so the answer is 5/(x+6)
lisa2345
  • lisa2345
d?
UsukiDoll
  • UsukiDoll
I have to go for a bit... xD need a break xD!
lisa2345
  • lisa2345
okay
lisa2345
  • lisa2345
You there?
lisa2345
  • lisa2345
hello?
UsukiDoll
  • UsukiDoll
I have to go eat dinner. I'll be back
lisa2345
  • lisa2345
okay :)

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