help me on this please..
The lower edge of a mural, 12 ft high, is 6ft above an observer’s eye. Under the assumption that the
most favorable view is obtained when the angle subtended by the mural at the eye is maximum, at
what distance from the wall should the observer stand?
Stacey Warren - Expert brainly.com
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tan X = 18/x where x is distance of the eye from the wall
tan Y = 6/x
so tan X = 3 tan Y
tan ( X - Y) has to be a maximum
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I can't think of an analytical way to do this
but using the fact that tan X = 3 tan Y and a trial and error numerical method
I get X = 60 and Y = 30
so the angle subtended by the mural = 30 degrees
and the distance from the eye to the wall is easy to calculate
tan 30 = 6 / x
x = 6 / tan 30
this is at best an approximate answer
i dont understand how u get x=60 and y=30?
tan X = 3 tan Y
i used trial and error
i tried X = 55
so tan 55 = 3 tan Y
this gave Y = 25.45 and X_Y = 29.54
X = 59
this gave X - Y= 29.1
X = 61 gave X - Y = 29.98
X = 60 gave X - Y= 30
so X - Y seems to peak at 30 degrees