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anonymous
 one year ago
An archway will be constructed over a walkway. A piece of wood will need to be curved to match a parabola. Explain to Maurice how to find the equation of the parabola given the focal point and the directrix (8).
d = (square root) (Xv2  3)^2 + (Yv2  6)^2
d = (square root) (Yv2  8)^2
I need to something like 1/8x^2 + 5/4x + 23/8 = y
(example given by school)
Its to do an arc.
I got to Xv2^2 6Xv2 + 9 + Yv2^2 8Yv2 + 16 = ???
anonymous
 one year ago
An archway will be constructed over a walkway. A piece of wood will need to be curved to match a parabola. Explain to Maurice how to find the equation of the parabola given the focal point and the directrix (8). d = (square root) (Xv2  3)^2 + (Yv2  6)^2 d = (square root) (Yv2  8)^2 I need to something like 1/8x^2 + 5/4x + 23/8 = y (example given by school) Its to do an arc. I got to Xv2^2 6Xv2 + 9 + Yv2^2 8Yv2 + 16 = ???

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You are forgetting the weird exponent that is below the number. I don't know if that effects the equation at all though. What I'm supposed to get is something like \[\frac{ 1 }{ 8 } x^2 + \frac{ 5 }{ 4 } x + \frac{ 23 }{ 8 } = y\] Which someone how becomes this 0.13x^2 + 1.25x + 2.88 (Not my problem, its their example)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Expand it? And give me a second, I'll stitch together some screenshots of what they gave for instructions.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I don't really understand any of this as I was horrible at algebra. I need it like what I said before, "0.13x^2 + 1.25x + 2.88" so I can put it in stupid geogebra to submit for my project.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Because I have to put it into geogebra, or I don't get a grade.

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.1so let's check... the focus is at (3, 6) and directrix is at y = 8

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.1great so using the distance formula method pick a point P(x, y) on the parabola distance Focus to P \[d = \sqrt{(x  3)^2 + (y  6)^2}\] P to the directrix \[d = \sqrt{x x)^2 + (y  8)^2}\] equating and squaring you get \[(x 3)^2 + (y  6)^2 = (y  8)^2\] now subtract (y  6)^2 from both sides \[(x 3)^2 = (y 8)^2  (y 6)^2 \] does that make sense..?

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.1so simplify the right hand side \[(x3)^2 = y^2  16y + 64  y^2 + 12y  36\] which becomes \[(x 3)^2 = 4y + 28\] factor the right hand side \[(x 3)^2 = 4(y  7)\] does that make sense...?

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.1make y the subject \[\frac{(x 3)^2}{4} + 7 = y\] you can enter the equation as its written above into Geogebra...

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.1it will then write the equation in expanded form with decimal coefficients...

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.1and I just graphed the parabola in geogebra and it worked perfectly...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0how do you graph it in it?

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.1just enter the equation I've written above \[y = \frac{(x 3)^2}{4} + 7\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0y = 0.25x^2 + 1.5x + 4.75?
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