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ummm 4 sin=-1?

or 2sin=-1?

yes...
so 2 would be
tan^2 = -3/2 sec
sin/cos ^2 = -3/2 1/cos = sin^2/cos=-3/2 ?

pi/3 and 5pi/3

??

ok... so if you are working in radians
the angles are
\[\pi + \theta~~and~~~2\pi - \theta\]

Now you lost me completely.

But there must also be a second one... so pi/6 and 3pi/6?

oops 4th quadrant is
\[2\pi - \frac{\pi}{6}\]

Still confused. It cant be negative....

pi/6?!?!?!?

and 2pi/6 = pi/3???

yes it can here is a graph of the sin curve |dw:1433490149420:dw|

none of my choices are negative though,

this is still for the first one?

pi/3, 5pi/3
2pi/3. 4pi/3
pi/6, 3pi,6
7pi/6, 11pi/6

so like d?

yes... we are still working on the 1st equation...

so like.... that's my guess

put it into your calculator
does sin(7pi/6) = -1/2 and does sin(11pi/6) = -1/2
try it

I can use the unit circle too, yes?

if so, it is yes for both

well there you go... sin can be negative... and the angles are larger then pi radians...

so thats the answer? no more steps?

well as I said... that's my best guess...
and you told me the unit circle agreed...

so for 2... tan^2 = -3/2sec
(sin/cos )^2= -3/2 1/cos
??

the unit circle produces the sin curve... that's important

trig is not my best section...

then multiply both sides by cos^2\[\sin^2(\theta) = \frac{-3 \cos(\theta)}{2}\]
is that ok..?

yes.. and then i square root everything?

okay.. so cross cancel the cos?

how do i set it up

but how since theres more than 1?

then only consider the value that is less than 1... a solution that is greater than 1 is undefined

hope it made some sense... and good luck with your assessment task.

3.2+/- sqrt -3/2^2+4
-----
2
so 4.95 and 1.45?

how do u convert from radians to degrees again...?