anonymous
  • anonymous
simplify [√(x+16)]-4
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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Adi3
  • Adi3
why dont u try first
anonymous
  • anonymous
rewrite (srqt(x+16))^-4
anonymous
  • anonymous
[(x+16)^1/2]^-4

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More answers

anonymous
  • anonymous
[x+16]^(1/2*-4) [x+16]^(-4/2) [x+16]^(-2)
anonymous
  • anonymous
[sqrt(x-16)]-4 @aj01 this is the problem ☺
anonymous
  • anonymous
okay
anonymous
  • anonymous
I dont know how to solve it, pls help.
anonymous
  • anonymous
i did solve it for you above
anonymous
  • anonymous
[(x+16)^1/2]^-4 [x+16]^(1/2*-4) [x+16]^(-4/2) [x+16]^(-2)
anonymous
  • anonymous
that -4 is not an exponent, it comes after the radical.
anonymous
  • anonymous
i c
anonymous
  • anonymous
[(x+16)^.5]-4 adding 16/16 to x [(16/16x+16)^.5]-4 [(16(x/16+1))^.5]-4 4(x/16+1)^.5-4 4(sqrt(x/16-1)^.5-1)
anonymous
  • anonymous
i think the sqrt(x+16)-4 is simpler
anonymous
  • anonymous
\[\sqrt{x+16}-4=(x+16)^{\frac{1}{2}}-4=(x+16)^{\frac{2}{4}}-2^2=((x+16)^{\frac{1}{4}})^2-2^2\] Now apply \[a^2-b^2=(a+b)(a-b)\]
Jack1
  • Jack1
curious... is it to the power of (-4) or is it just.... minus 4...?

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