Advanced Algebra, triangle

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- anonymous

Advanced Algebra, triangle

- jamiebookeater

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- anonymous

Use the formulas a = x^2 – y^2, b = 2xy, c = x^2 + y^2 to answer this question.
One leg of a right triangle has length 11 and all sides are whole numbers. Find the lengths of the other two sides.
The other leg=
And the hypotenuse=

- anonymous

Well since this is a right angle triangle, we can already use the properties of Pythagoras' theorem. But before, we start on doing anything, we have to let one side equal to 11.
I recommend not the hypotenuse to be 11

- anonymous

it has been a long time since i have even seen Pythagoras' theorem

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- anonymous

Can you still remember at all? You can quickly search it up via the net ^^

- anonymous

give me a second to go look it up,(i c\just came back from the bathroom)

- anonymous

a^2+b^2=c^2

- anonymous

Right

- anonymous

So how do you think, you should approach this question?

- anonymous

11^2+b^2=c^2

- anonymous

yeap
Just solve for that, and make on of the pro numerals the subject

- anonymous

Just remember, that we are working in 'x' and 'y' so you have to mold your equations around those variables

- anonymous

hmmm
it is 9:27AM over here and my mind is still waking up :/

- anonymous

no worries it is 11:29 pm over here

- anonymous

is there a formula u can give me or an example?

- anonymous

Alright no problem

- anonymous

|dw:1433511154354:dw|

- anonymous

But we have to let either 'a' or 'b' equal 11, since that is out clue here ~

- anonymous

that writing is a tiny bit eligible...

- anonymous

Sorry its freezing cold at the moment, and its on the computer so its quite hard to draw with a mouse ><

- anonymous

The hypotenuse is: C = x^2 + y^2
a = x^2 - y^2
b = 2xy
So we are given one side is equivalent to 11, so which side you will to make it 11?

- anonymous

b, it seems the best choice

- anonymous

Okay, so just solve from there and let see what you get

- anonymous

well i am brain dead or i just cant remember how to do this..........

- anonymous

it is sad because i use to be very good at math

- anonymous

Well... its time to redeem yourself in this question ^^
Everyone has their moments in mathematics :)

- anonymous

ill just close this question and go on to something else. :/

- anonymous

b = 2xy
b = 11
so 11 = 2xy
Thus ->
x = 11 / 2y
Try substituting that into a now, and let see what you get

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