someone please explain how to solve this Given ΔABC, m∠A = 60°, b = 9 and c = 6. Find m∠B. Round to the nearest whole degree. A) 8° B) 41° C) 71° D) 79°

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someone please explain how to solve this Given ΔABC, m∠A = 60°, b = 9 and c = 6. Find m∠B. Round to the nearest whole degree. A) 8° B) 41° C) 71° D) 79°

Trigonometry
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do you know the law of sines?
its something like soh cah toa
you can only use that if you know it's a right triangle

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Other answers:

it is soh cah toa
how about a/sinA=b/sinB=c/sinC
but which side is which
i dont know theres no picture
so try soh can toa, do you know what it stands for? *tip: c usually= hypotenuse
cah sorry not can
well then why is b bigger than c
no i dont understand th esoh cah toa i looked it up and i dont understand
Sine Opposite Hypotenuse Cosine Adjacent Hypotenuse Tangent Opposite Adjacent
|dw:1433517992401:dw|
you do not know that this is a right angle so you cannot use the standard trig functions
what im so confused
then what do i use
|dw:1433518102874:dw| the general triangle is drawn above
how do you solve it
|dw:1433518184180:dw|
so FIRST use law of cosines to find a a^2 = b^2 + c^2 -2bc cosA then use law of sines a/sinA = b/sinB
uhh can you show me?
im still a little lost
The equations you need are above, and the values of a,b and A are given in the question and in my drawing this question is about cosine and sine rules use them to solve as described above FIRST solve a from cosine rule THEN solve B from sine rule
so for a i got 6210?
given that the other 2 sides ar 6, & 9 is that a likely answer?
no thats y im so confused i dont know where im going wrong
a^2 = b^2 + c^2 -2bc cosA you are trying to find a first write down what is b what is c what is cos A
b is 9 9^2 is 81
c is 6 6^2 36
ok good soo ... 2bc cosA =??
cosA is 0.5
2bc cosA= 2916?
2* 9 * 6 * 0.5 =
54
i thought we were supposed to use the squared number like 81 nd 36
a^2 = b^2 + c^2 -2bc cosA the squared numbers are part of it - but not in the 2bc cos A
so do i plug in the numbers to the equation? @MrNood

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