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anonymous
 one year ago
someone please explain how to solve this
Given ΔABC, m∠A = 60°, b = 9 and c = 6. Find m∠B. Round to the nearest whole degree.
A)
8°
B)
41°
C)
71°
D)
79°
anonymous
 one year ago
someone please explain how to solve this Given ΔABC, m∠A = 60°, b = 9 and c = 6. Find m∠B. Round to the nearest whole degree. A) 8° B) 41° C) 71° D) 79°

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0do you know the law of sines?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0its something like soh cah toa

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you can only use that if you know it's a right triangle

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0how about a/sinA=b/sinB=c/sinC

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0but which side is which

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i dont know theres no picture

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so try soh can toa, do you know what it stands for? *tip: c usually= hypotenuse

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0well then why is b bigger than c

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0no i dont understand th esoh cah toa i looked it up and i dont understand

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Sine Opposite Hypotenuse Cosine Adjacent Hypotenuse Tangent Opposite Adjacent

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1433517992401:dw

MrNood
 one year ago
Best ResponseYou've already chosen the best response.1you do not know that this is a right angle so you cannot use the standard trig functions

MrNood
 one year ago
Best ResponseYou've already chosen the best response.1dw:1433518102874:dw the general triangle is drawn above

MrNood
 one year ago
Best ResponseYou've already chosen the best response.1so FIRST use law of cosines to find a a^2 = b^2 + c^2 2bc cosA then use law of sines a/sinA = b/sinB

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0uhh can you show me?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0im still a little lost

MrNood
 one year ago
Best ResponseYou've already chosen the best response.1The equations you need are above, and the values of a,b and A are given in the question and in my drawing this question is about cosine and sine rules use them to solve as described above FIRST solve a from cosine rule THEN solve B from sine rule

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so for a i got 6210?

MrNood
 one year ago
Best ResponseYou've already chosen the best response.1given that the other 2 sides ar 6, & 9 is that a likely answer?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0no thats y im so confused i dont know where im going wrong

MrNood
 one year ago
Best ResponseYou've already chosen the best response.1a^2 = b^2 + c^2 2bc cosA you are trying to find a first write down what is b what is c what is cos A

MrNood
 one year ago
Best ResponseYou've already chosen the best response.1ok good soo ... 2bc cosA =??

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i thought we were supposed to use the squared number like 81 nd 36

MrNood
 one year ago
Best ResponseYou've already chosen the best response.1a^2 = b^2 + c^2 2bc cosA the squared numbers are part of it  but not in the 2bc cos A

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so do i plug in the numbers to the equation? @MrNood
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