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AmTran_Bus

  • one year ago

log question

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  1. AmTran_Bus
    • one year ago
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    If I had ln(3x-10)=2

  2. AmTran_Bus
    • one year ago
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    I know you multiply each side by e

  3. AmTran_Bus
    • one year ago
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    But does it make the right side 2*e or e^2?

  4. anonymous
    • one year ago
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    You do not multiply both sides by e, you have to apply exponential on both sides

  5. anonymous
    • one year ago
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    Firstly multiply \(e\) both the sides..

  6. NotTim
    • one year ago
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    NotMultiply.

  7. anonymous
    • one year ago
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    \(ln\) is basically called Natural Log, it is by default having base as \(e\)..

  8. NotTim
    • one year ago
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    M4th got it.

  9. anonymous
    • one year ago
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    remember that \[e^{ln(x)} = x\]

  10. anonymous
    • one year ago
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    \[\ln = \color{green}{\ln _e}\]

  11. AmTran_Bus
    • one year ago
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    Yea, I know that. But the right side, the solution says you say e^2, and I would have said 2e.

  12. AmTran_Bus
    • one year ago
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  13. anonymous
    • one year ago
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    Applying exponential on both side, you get: \[e^{ln(3x-10)} = e^{2}\]

  14. anonymous
    • one year ago
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    you are multiplying by "e" on the right side, that is wrong

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