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anonymous

  • one year ago

Danny keeps five cards with the picture of a cat and six cards with the picture of a dog on a table face down, so the pictures are hidden. He mixes up the cards then turns one card over and finds the picture of a dog on it. He removes this card from the table and turns over another card. What is the probability that the card Danny turns over has a dog on it? fraction 4 over 10 fraction 5 over 11 fraction 5 over 10 fraction 5 over 6

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  1. anonymous
    • one year ago
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    @Michele_Laino

  2. anonymous
    • one year ago
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    @Michele_Laino plz help?

  3. anonymous
    • one year ago
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    when one card with dog picture is removed,remaining cards with picture of dog=?

  4. anonymous
    • one year ago
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    um 1 left

  5. anonymous
    • one year ago
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    out of 6, one card is removed.

  6. anonymous
    • one year ago
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    5

  7. anonymous
    • one year ago
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    how many total no. of cards now ?

  8. Michele_Laino
    • one year ago
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    the probability is equal to the subsequent ratio: favorable outcomes/possible outcomes

  9. anonymous
    • one year ago
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    so the answer is 5/10

  10. anonymous
    • one year ago
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    correct.

  11. Michele_Laino
    • one year ago
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    now at the second attempt we have 10 cards in total, and five of them are cards with the picture of a dog, so our probability, is: 5/10=...

  12. anonymous
    • one year ago
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    ok i have a few more questions if that is ok it wont take long @Michele_Laino

  13. anonymous
    • one year ago
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    i will put it in a new question

  14. Michele_Laino
    • one year ago
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    ok!

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