Determine whether the point (2, 0) is a solution to the system of equations. Explain your reasoning in complete sentences.

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Determine whether the point (2, 0) is a solution to the system of equations. Explain your reasoning in complete sentences.

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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just put these point in the place of variable and if they satisfy the equeation then they are solution sets ......
how do I know if they satisfy them? I plugged it in and i got g(x) = 8 and f(x) = 2

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That is a picture of the graph they gave us
where tow lines will cut each other i will be the solution set of equeations...
Oh okay so it should be (0,2) ?
If you have a graph showing all of the equations, any solution to all of the equations will be a point at which all of the equations intersect. Is (2,0) such a point?
For the same value of \(x\), both \(f(x)\) and \(g(x)\) must be equal for that value of \(x\) to be a solution.
Oh so I just plug in 2 for x in both of my solutions and 0 for y?
\[y = f(x) = |x-1|+1\]\[y = g(x) = 3x+2\]If we think \(x=2\) might be a solution, then \[f(2) = g(2)\]but \[f(2) = |2-1|+1 = 2\]and \[g(2) = 3(2) +2 = 8\] and those are not equal...
Yes, you could also do it that way as a check: \[0 = f(2) = |2-1|+1\checkmark\]so far, so good, but let's try the other equation, which also must work: \[0 = g(2) = 3(2)+2 = 8\]Bzzt, wrong! So \((2,0\) is NOT a solution to that system of equations.
sorry, \((2,0)\) is not a solution
Okay thats what I thought. Thank you.

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