Amy has 35 tiles of the same shape and size in a box. The colors of and amounts of the tiles are shown below:
12 red tiles
8 yellow tiles
15 pink tiles
Without looking in the box, Amy takes out a tile at random. She then replaces the tile and takes out another tile from the box. What is the probability that Amy takes out a yellow tile in both draws?
8 over 35 multiplied by 7 over 34 equal 56 over 1190
8 over 35 multiplied by 8 over 35 equal 64 over 1225
8 over 35 plus 7 over 34 equal 517 over 1190
8 over 35 plus 8 over 35 equal 560 over 1225

- anonymous

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- anonymous

@Michele_Laino

- anonymous

@Michele_Laino

- Michele_Laino

we have 8 favorable outcomes
and
12+8+15= 35 possible outcomes
so
probability=
favorable outcomes/ possible outcomes=...

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## More answers

- Michele_Laino

that is the probability associated to a single extraction

- Michele_Laino

favorable outcomes = 8
possible outcomes = 35
\[\Large \frac{{{\text{favorable outcomes}}}}{{{\text{possible outcomes}}}} = ...\]

- anonymous

so i have to divide

- Michele_Laino

yes!

- anonymous

@Michele_Laino

- Michele_Laino

the probability is 8/35 it is simple!

- Michele_Laino

for a single extraction

- anonymous

so what about the other part

- Michele_Laino

for second extraction, the probability is the same, namely it is 8/35, since Amy replaces the tile into the box. Now the requested probability is the product of the two probabilities, namely:
probability = (8/35)*(8/35)=...?

- anonymous

64/1225

- Michele_Laino

that's right!

- anonymous

Yay!

- Michele_Laino

:)

- anonymous

A coin was flipped 150 times. The results of the experiment are shown in the following table:
Heads Tails
90 60
Which of the following best describes the experimental probability of getting heads?
It is 10% higher than the theoretical probability.
It is 10% lower than the theoretical probability.
It is equal to the theoretical probability for this data.
The experimental probability cannot be concluded from the data in the table.

- Michele_Laino

the theoretical probability is 1/2
since we have two possible outcomes, namely a head and a tail
and we have one favorable outcome, namely a head, so
probability = 1/2= 0.5
The experimental probability to get a head is
90/150=...

- Michele_Laino

since we have 90 favorable cases and 150 possible cases or outcomes

- anonymous

0.6

- anonymous

SO IT 10% lower than the theoretical probability

- Michele_Laino

now the difference between the experimental probability and the theoretical probability is:
0.6-0.5=...

- anonymous

so its 10% higher

- Michele_Laino

that's right!

- anonymous

so the answer is A

- Michele_Laino

yes!

- anonymous

yay!!!! last question sorry

- Michele_Laino

ok!

- anonymous

The number of marbles of different colors stored in a hat is listed below:
8 red marbles
10 green marbles
6 blue marbles
Without looking in the hat, Tessa takes out a marble at random. She replaces the marble and then takes out another marble from the hat. What is the probability that Tessa takes out a blue marble in both draws?
fraction 1 over 16
fraction 1 over 12
fraction 1 over 4
fraction 1 over 2

- Michele_Laino

here we have
8+10+6= 24 possible outcomes
and we have
6 favorable outcomes
so the probability associated to a single extraction is:
p= 6/24
please simplify that fraction

- anonymous

0.25

- Michele_Laino

we can divide both numerator and denominator by 6, wha do you get?

- anonymous

divide what?

- anonymous

oh 1/4

- Michele_Laino

that's right!

- anonymous

so is that the answer @Michele_Laino

- Michele_Laino

now, the probability associated to the second extraction is the same, namely 1/4.
So the requested probability is given by the product between the above probabilities, namely
p= (1/4)*(1/4)=...?

- Michele_Laino

what is:
\[\Large P = \frac{1}{4} \times \frac{1}{4} = ...?\]

- anonymous

Dang it

- anonymous

i just submitted my test

- anonymous

and i got it wrong

- anonymous

because i forgot to do the last part

- anonymous

):

- anonymous

but i got a 87% percent on my test

- Michele_Laino

so have you passed it?

- anonymous

yes i did

- Michele_Laino

CONGRATULATIONS!!!!!

- anonymous

im finished with math until next year yay!!!!!!!!

- Michele_Laino

:)

- anonymous

Im going to be in 8th grade

- Michele_Laino

ok!! :)

- anonymous

but Atleast i got a high B on my test !

- anonymous

and i have a A in Math!

- Michele_Laino

good job!!

- anonymous

Thank you so much you really helped me undertand what i was doing. But i will be coming back just in case i need help lol!

- Michele_Laino

ok! :)

- Jack1

hi marc
just if u could, please only post 1x question per post
cheers

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