Can somebody show me how to factor this quadratic equation?

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Can somebody show me how to factor this quadratic equation?

Mathematics
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2x^2 – 5x – 3
2x2-(6-1)x-3=2x2-6x+x-3
\[x=(-b \pm \sqrt{b ^{2}-4ac})\div2a\]

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2*3=6 make factor of 6 as difference is middle term that is 5
Oh! Quadratic formula. Yes. Would the solved product be the factored form?
I'm going to be putting it into a rational expression :)
I'm fairly sure, yes.
I'll post what I got in a minute. Could ya'll check it over?
Sure :)
I got 3 or -0.5. Correct? And also, if that's factored, how do I know which to choose...?
Okay I don't know if I messed up or not but I got 5.83? I'm probably very wrong. xD I'm sorry.
That's alright :/ I'll have to try elsewhere. Thanks anyway! I just double checked my answers, here, though http://www.math.com/students/calculators/source/quadratic.htm

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