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anonymous

  • one year ago

What are the odds of rolling a 6 on a regular six sided die?

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  1. anonymous
    • one year ago
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    @Michele_Laino

  2. anonymous
    • one year ago
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    i think its 1:6 @Michele_Laino

  3. Michele_Laino
    • one year ago
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    I think that they are 1, 3, and 5

  4. Michele_Laino
    • one year ago
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    namely the odd numbers are 1, 3, and 5

  5. Michele_Laino
    • one year ago
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    the requested probability is: \[\frac{{{\text{favorable outcomes}}}}{{{\text{possible outcomes}}}} = \frac{1}{6}\]

  6. anonymous
    • one year ago
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    IS ODDS DIFFERENT THE PROBABILITY @Michele_Laino

  7. anonymous
    • one year ago
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  8. anonymous
    • one year ago
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    1/6

  9. anonymous
    • one year ago
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    but isnt probability and odds different

  10. Michele_Laino
    • one year ago
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    for example, the odds is the probability when all the possible outcomes are different each from other

  11. anonymous
    • one year ago
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    so 1:6 would be correct?

  12. anonymous
    • one year ago
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    for odds?

  13. Michele_Laino
    • one year ago
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    I'm pondering

  14. anonymous
    • one year ago
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    @Odds is defined as success : failures. There are two numbers greater than or equal to 5. Those numbers are 5 and 6. The failures would be the numbers that are not greater than or equal to 5. Those numbers are 1, 2, 3, and 4. This means that odds is 2 : 4 or 1 : 2.

  15. anonymous
    • one year ago
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    im confused.

  16. anonymous
    • one year ago
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    probabily would be 1:6 but for odds it would be 1:5 correct?

  17. Michele_Laino
    • one year ago
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    here is the right definition of odds: "odds is the ratio between the probability that an event occurs and the probability that the same event not occurs" so for question #1 probability to get "m" = 1/7 probability to get not an "m" = 1-(1/7)=6/7 \[\Large odds = \frac{{1/7}}{{6/7}} = \frac{1}{6}\]

  18. Michele_Laino
    • one year ago
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    another example: for a six sided dice, we have: probability to get a "6" = 1/6 probability to get not a "6" = 1-(1/6)= 5/6 so: \[\Large odds = \frac{{1/6}}{{5/6}} = \frac{1}{5}\]

  19. Michele_Laino
    • one year ago
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    finally: question #3 probability to get "g" = 2/7 probability to get not a "g" = 1-(2/7) = 5/7 so: \[\Large odds = \frac{{2/7}}{{5/7}} = \frac{2}{5}\]

  20. anonymous
    • one year ago
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    Such a complicated process to find out something so simple! Would've never guessed. Thanks for broadening my horizons :) @Michele_Laino

  21. Michele_Laino
    • one year ago
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    :)

  22. Jack1
    • one year ago
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    1 chance in 6 possibilities ;)

  23. anonymous
    • one year ago
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    1/6

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