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- anonymous

Algebra help!!

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- anonymous

Algebra help!!

- schrodinger

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- anonymous

You are building a concrete deck around a rectangular swimming pool. The pool is three times as long as it is wide. The deck will have a constant width of four feet. In order to have enough concrete, you have calculated the area of the deck to be 832 square feet.
What are the dimensions of the pool?
Interpret the concepts of the task and translate them into mathematics. (RESTATE THE PROBLEM IN YOUR OWN WORDS)

- NotTim

draw a diagram first.

- anonymous

|dw:1433525673600:dw|

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- NotTim

Yeah.

- anonymous

i know the answer to the question i just need it restated

- NotTim

Important part of science isn't knowing the answer, but knowing the proper process.

- welshfella

Let the width of the pool be x feet
then the length = 3x feet
the area of the deck+ pool is 834 feet
the width of the pool including the deck = x + 2*4 = x + 8 feet
the length ........................................... = 3x + 8 feet
therefore the area of the pool + deck
(x + 8)(3x + 8) = 834

- NotTim

You gave it away too fast.

- anonymous

i know this already. just need the problem restated

- welshfella

oh - sorry i misread the question

- anonymous

its cool. can you help though?

- welshfella

I'm not sure exactly what they want
I would have thought if you explained your reasoning - using algebra to interpret the problem and working it out would be a sufficient answer.

- anonymous

ok thx

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