A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 one year ago
help
anonymous
 one year ago
help

This Question is Closed

NotTim
 one year ago
Best ResponseYou've already chosen the best response.1Rearrange so that "y" is 'alone'

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so it would be x^2+6y

NotTim
 one year ago
Best ResponseYou've already chosen the best response.1make it so it is like: y=....

NotTim
 one year ago
Best ResponseYou've already chosen the best response.1you have to divide both sides by 6 so that 6y is just y.

NotTim
 one year ago
Best ResponseYou've already chosen the best response.1you have to rearrange it frist.

NotTim
 one year ago
Best ResponseYou've already chosen the best response.1divide both sides by 6.

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2it is simple: the graph of y=x^2 is a parabole which passes at the origin of the coordinate system: dw:1433527737795:dw

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2the function: x^2=6y can be rewritten as below: \[\Large y = \frac{1}{6}{x^2}\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2where I have used the suggestion of @NotTim

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2I have divide both sides by 6, as @NotTim well said

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2Now the graph of your function: \[\Large y = \frac{1}{6}{x^2}\] is similar to the graph of the function y= x^2. We have the subsequent drawing: dw:1433528004632:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0like u have to find focus, dirretrix

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2it is another parabola, which passes at the origin of the coordinate system

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0like u have to find focus, dirretrix

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2here are the formulas to find focus and directrix:

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2we have to start from this equation: \[y = a{x^2} + bx + c\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2by comparison with our equation, we get: a= 1/6, b=0, and c=0, right?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2now the general formula for focus and directrix are: \[\Large \begin{gathered} Focus = \left( {  \frac{b}{{2a}},\frac{{1  {b^2} + 4ac}}{{4a}}} \right) \hfill \\ \hfill \\ y =  \frac{{1 + {b^2}  4ac}}{{4a}},\quad directrix \hfill \\ \end{gathered} \]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2please substitute the parameters: a=1/6, b=c=0

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2what do you get?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1433528576564:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so we can eliminate that

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2\[\Large y =  \frac{{1 + {b^2}  4ac}}{{4a}} =  \frac{{1 + 0  4 \times \left( {1/6} \right) \times 0}}{{4/6}}\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2\[\large y =  \frac{{1 + {b^2}  4ac}}{{4a}} =  \frac{{1 + 0  4 \times \left( {1/6} \right) \times 0}}{{4/6}}\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2that is the directrix

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0how would u find that

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2the focus is: \[\Large Focus = \left( {  \frac{0}{{2/6}},\frac{{1  0 + 4/6 \times 0}}{{4/6}}} \right)\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2those are general formulas, which can be derived

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2so after a simplification, we get: \[\Large \begin{gathered} Focus = \left( {0,\;\frac{3}{2}} \right) \hfill \\ \hfill \\ directrix:\quad y =  \frac{3}{2} \hfill \\ \end{gathered} \]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2please check my result above
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.