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- cutiecomittee123

x^2+4y=100
4y-x^2=-20
How in the world so I solve this system of equations please help fast!
Do I use substitution? I don't clearly see how I would solve for x or y in either equation.

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- cutiecomittee123

- jamiebookeater

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- anonymous

you can use substitution because x^2 on the first equation is positive and negative on the second equation. They will cancel out

- anonymous

*as i was, the 4y's will cancel out

- cutiecomittee123

so add them together

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- cutiecomittee123

I get y=10

- anonymous

yup x^2-(-x^2)=2x^2 and then 100-(-20)=120 2x^2=120 120/2=60 x^2=60 and then take the square root

- cutiecomittee123

yeah so square root of 60 = x

- anonymous

exactly, and whatever x equals you plug it into to one of the equations to find y

- cutiecomittee123

I plugged it into the second equation and it worked. So does that mean there is only one solution?

- anonymous

no the number you plugged in is the answer for x. The answer you got after you plugged it in is y

- anonymous

remember, there is an x and a y so there has to be at least 2 answers, one for each letter

- cutiecomittee123

Yeah so (sqrt60, 10) is the only solution?

- cutiecomittee123

I got the answer wrong it was actually (6,4) :(((

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