anonymous
  • anonymous
Prove that the two circles shown below are similar
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
http://learn.flvs.net/webdav/assessment_images/educator_geometry/v15/module09/09_08_9.jpg
anonymous
  • anonymous
@is3535
imqwerty
  • imqwerty
cookie error comes when i open the link

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anonymous
  • anonymous
SAME WITH ME.
anonymous
  • anonymous
humm okay one sec let me screen shot the image and post it :p
is3535
  • is3535
me to
anonymous
  • anonymous
1 Attachment
anonymous
  • anonymous
there u go let me know if that works
imqwerty
  • imqwerty
yes it works
is3535
  • is3535
no ther no simliar B is 5 and D 7 i say
anonymous
  • anonymous
okay can yall help me? this is what i have so far.. idk if its right All circles are similar because you can scale one circle to be the same size as another (bigger or smaller) circle. They effectively have the same shape.
is3535
  • is3535
im not 1000 % that i said
anonymous
  • anonymous
humm... i dont think that is right haha
anonymous
  • anonymous
you can go from one figure to the other with a translation and a dilation, does that make them similar? im not so sure...
anonymous
  • anonymous
what if i say this?? Theorem: Any two circles are similar. Proof: Given a circle of radius r and a second circle of radius R , perform a translation so that their centers coincide. A dilation from the common center of the circles with scale factor R takes the points of one circle and maps them onto the second. Thus we have mapped one circle onto the other via a translation and a dilation. The circles are simila
anonymous
  • anonymous
First circle with center (-1,5) and radius=4 second circle with center (7,4) and radius =2
anonymous
  • anonymous
@CayleeS23 ... where did you get that theorem from?
anonymous
  • anonymous
Their similar because
anonymous
  • anonymous
http://www.jamestanton.com/wp-content/uploads/2012/03/Curriculum-Newsletter_January-2013.pdf
anonymous
  • anonymous
hello???
anonymous
  • anonymous
looks like they are similar, and the proof would be what @CayleeS23 posted before...
anonymous
  • anonymous
im confused...
anonymous
  • anonymous
listen
anonymous
  • anonymous
very simple
anonymous
  • anonymous
their both round and they both have no sides
anonymous
  • anonymous
proved
anonymous
  • anonymous
feel free to fan and medal me
anonymous
  • anonymous
no that doesnt prove anything haha get otta here dude...
anonymous
  • anonymous
i guess a better proof would be taking the ratio of their perimeter to their radius for each of them, you will get the same in both cases, actually you get: \[2\pi\] for any circle so they are similar
anonymous
  • anonymous
I tried. I failed/
anonymous
  • anonymous
hey sometimes the answer is easier than you think
anonymous
  • anonymous
ohh okay that makes since so should i just put that?? proof would be taking the ratio of their perimeter to their radius for each of them, you will get the same in both cases, actually you get: 2π for any circle so they are similar
anonymous
  • anonymous
can u show me how u did that math? to prove that they are both 2pi
anonymous
  • anonymous
this is pi|dw:1433531216624:dw|
anonymous
  • anonymous
if you look for the definition of similarity you find somethng like this: "Two figures that have the same shape are said to be similar.When two figures are similar, the ratios of the lengths of their corresponding sides are equal." Applied to a rectangle you would use the ratio between the sides, because that is what defines the rectangle shape, for a circle, the important quantity is its radius
anonymous
  • anonymous
@Gunboss that is exactly what i was saying...
anonymous
  • anonymous
:D
anonymous
  • anonymous
hum okay... @Gunboss pi means 3.14 in math terms you are thinking of pie like food haha
anonymous
  • anonymous
I guess. (btw my pi is better)
MrNood
  • MrNood
Given a circle of radius r and a second circle of radius R , perform a translation so that their centers coincide. A dilation from the common center of the circles with scale factor k=R/r takes the points of one circle and maps them onto the second. Thus we have mapped one circle onto the other via a translation and a dilation. The circles are similar.

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