At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
cookie error comes when i open the link
SAME WITH ME.
humm okay one sec let me screen shot the image and post it :p
there u go let me know if that works
yes it works
no ther no simliar B is 5 and D 7 i say
okay can yall help me? this is what i have so far.. idk if its right All circles are similar because you can scale one circle to be the same size as another (bigger or smaller) circle. They effectively have the same shape.
im not 1000 % that i said
humm... i dont think that is right haha
you can go from one figure to the other with a translation and a dilation, does that make them similar? im not so sure...
what if i say this?? Theorem: Any two circles are similar. Proof: Given a circle of radius r and a second circle of radius R , perform a translation so that their centers coincide. A dilation from the common center of the circles with scale factor R takes the points of one circle and maps them onto the second. Thus we have mapped one circle onto the other via a translation and a dilation. The circles are simila
First circle with center (-1,5) and radius=4 second circle with center (7,4) and radius =2
@CayleeS23 ... where did you get that theorem from?
Their similar because
looks like they are similar, and the proof would be what @CayleeS23 posted before...
their both round and they both have no sides
feel free to fan and medal me
no that doesnt prove anything haha get otta here dude...
i guess a better proof would be taking the ratio of their perimeter to their radius for each of them, you will get the same in both cases, actually you get: \[2\pi\] for any circle so they are similar
I tried. I failed/
hey sometimes the answer is easier than you think
ohh okay that makes since so should i just put that?? proof would be taking the ratio of their perimeter to their radius for each of them, you will get the same in both cases, actually you get: 2π for any circle so they are similar
can u show me how u did that math? to prove that they are both 2pi
this is pi|dw:1433531216624:dw|
if you look for the definition of similarity you find somethng like this: "Two figures that have the same shape are said to be similar.When two figures are similar, the ratios of the lengths of their corresponding sides are equal." Applied to a rectangle you would use the ratio between the sides, because that is what defines the rectangle shape, for a circle, the important quantity is its radius
@Gunboss that is exactly what i was saying...
hum okay... @Gunboss pi means 3.14 in math terms you are thinking of pie like food haha
I guess. (btw my pi is better)
Given a circle of radius r and a second circle of radius R , perform a translation so that their centers coincide. A dilation from the common center of the circles with scale factor k=R/r takes the points of one circle and maps them onto the second. Thus we have mapped one circle onto the other via a translation and a dilation. The circles are similar.