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I don't know the answer, but you should post the triangle for other people.

|dw:1433534714159:dw|

#nottim

@ <<---- to tag some
@ name

|dw:1433535491052:dw|
it's right triangle right ????

ok

^ right
so what did you got for 3rd side ?

im really behind and i just need answers
i Know it sound rude but im jugling 10 assignment

at the same time

welcome to openstudy!
that's not gonna happen you have to participate :-)

alright substitute a and c value solve for b :-)

\[\huge\rm 15^2 + b^2 = 25^2\]
b = ?

90

nope how did you get 90 ?

take square of 25 and 15

625 and 225

\[\huge\rm a^2+ 225 = 625\]
solve for a
move 225 to the right side

then subtract 225

yes right

then take square root

20

ys right

can we do another'

did you get that one ?
cos = ?
tan = ?

remember you need
tan x
and cos z

i got it

alright

|dw:1433539551579:dw|

sin^ theta =what ?
remember the identity ?

sin^2 theta =what ?
remember the identity ?

its a different question

yes ik :-)

|dw:1433539731456:dw|

i have to simplify

no

i realy need the answer i only have a couple hours to turn in everything

ok i understand

this is a different one

|dw:1433540518518:dw|

ill be serious

alright what's the statement ?

angle j

is it right triangle ?

no

did you apply law of cosines or law of sines ?

cosine

was it right?

gimme a sec i'll check

law of cosines when they gave you one angle
check your question again

then its 7

i din't say 35 is wrong ....
for law of cosine
you should have all 3 sides or at least one angle

thats the angle tho

what's the question
seems like you mssing something
look at the original question

are*

what is the measure of angle j in the triangle

take a screenshot

i'm saying they should gave u all 3 sides
or 2 sides one angle
that's not info to solve the question

|dw:1433541529143:dw|

yep now we can solve it
thanks!

sorry

nope 35 isn't right
you have to use law of sines

\[\huge\rm \frac{ \sin J}{ j } = \frac{ \sin I }{ i }\]
plug in numbers solve for J

j is opposite side of angle J|dw:1433541845296:dw|

\[(\sin 10/10)\]

sin is not 10
j side = 10

\[\huge\rm \frac{ \sin J}{ j } = \frac{ \sin I }{ i }\]
angle I = ?
side i = ?
j side = 10

i = 17

yes right so plug in

and angle I = ?

102

yes right

\[\huge\rm \frac{ \sin J}{ 10 } = \frac{ \sin (102) }{ 17 }\]
solve for angle J

83

i didn't get 83

oh sorry 97

i didn't get 97

what did you get?

how did you solve ?
show your work please :(

im new to this it will take a long tim

it's okay

how did you get 7 ? :o

did you use calculator ?

yes

what did u put into the calculator ?
parentheses are really important

sin/ 10=sin(102)/17

sin J**

http://www.wolframalpha.com/ use this one