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anonymous
 one year ago
Can someone please help me with Algebra 2B?
anonymous
 one year ago
Can someone please help me with Algebra 2B?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ (3\sqrt{2}2\sqrt{3})^2 }{ (3\sqrt{2})^{2}(2\sqrt{3})^2 }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Rationalize the denominator and simplify.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I will try to help yikes

tkhunny
 one year ago
Best ResponseYou've already chosen the best response.0Simplify for exploration... \(\dfrac{(ab)^{2}}{a^{2}  b^{2}}\) Do you see that this is the same structure?

tkhunny
 one year ago
Best ResponseYou've already chosen the best response.0Can you simplify the STRUCTURE by factoring?

tkhunny
 one year ago
Best ResponseYou've already chosen the best response.0\(\dfrac{(ab)^{2}}{a^{2}b^{2}} = \dfrac{(ab)(ab)}{(a+b)(ab)}\) How about now?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ (3\sqrt{2}2\sqrt{3})(3\sqrt{2}2\sqrt{3}) }{ (3\sqrt{2}+2\sqrt{3})(3\sqrt{2}2\sqrt{3}) }\] so then i can cancel out the \[(3\sqrt{2}2\sqrt{3}\] on both the top and the bottom ?

tkhunny
 one year ago
Best ResponseYou've already chosen the best response.0Okay, that was just a hint. This one turns out to be easier because "rationalize the denominator" doesn't actually mean anything for this problem. It's ALREADY rational!! \(\left(3\sqrt{2}\right)^{2}  \left(2\sqrt{3}\right)^{2} = 9\cdot 2  4\cdot 3 = 18  12 = 6\) How's that for Rational?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0OK but @tkhunny the original problem wasn't actually rational the problem I gave was just the step I was at. I need to get it so there is no denominator. The original problem was \[\frac{ 3\sqrt{2}2\sqrt{3} }{ 3\sqrt{2}+2\sqrt{3} }\] and then I multiplied by the conjugate. So if what we have right now is \[\frac{ (3\sqrt{2}2\sqrt{3})^2 }{ 6 }\] (if I understood you correctly) then I also need to get rid of the six but I don't know how.
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