## Madgirlwithabluebox one year ago Simplify the trigonometric expression. (will medal)

$\frac{ \sin^2\theta}{ 1+\cos \theta}$

2. freckles

sin^2(theta) can be written as 1-cos^2(theta) and guess what that can be factored

3. mathstudent55

Use the identity below (solved for $$\sin^2 \theta$$) $$\sin^2 \theta + \cos^2 \theta = 1$$ and do a substitution in the numerator. Then factor the numerator and reduce.

Im still really confused

5. anonymous

=(1-cosθ^2)/(1+cosθ)

6. anonymous

=(1-cosθ)(1+cosθ)/(1+cosθ) then we simplfy we know that a^2 - b^2=(a-b)(a+b) @Madgirlwithabluebox

7. anonymous

so we get after simplifying the result =(1-cosθ) did u understand @Madgirlwithabluebox

Uh no? I get that since there was (1+cosθ)/(1+cosθ) you simplified and got the answer but i dont understand anything else

9. anonymous

so? You understood it or no now ?

I think ,

11. freckles

does this make sense: assuming y not -1 simplifying (1-y^2)/(1+y) $\frac{1-y^2}{1+y}=\frac{(1-y)(1+y)}{1+y}=\frac{\cancel{(1+y)}(1-y)}{\cancel{1+y}}=1-y$