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Madgirlwithabluebox

  • one year ago

Simplify the trigonometric expression. (will medal)

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  1. Madgirlwithabluebox
    • one year ago
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    \[ \frac{ \sin^2\theta}{ 1+\cos \theta}\]

  2. freckles
    • one year ago
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    sin^2(theta) can be written as 1-cos^2(theta) and guess what that can be factored

  3. mathstudent55
    • one year ago
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    Use the identity below (solved for \(\sin^2 \theta\)) \(\sin^2 \theta + \cos^2 \theta = 1\) and do a substitution in the numerator. Then factor the numerator and reduce.

  4. Madgirlwithabluebox
    • one year ago
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    Im still really confused

  5. anonymous
    • one year ago
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    =(1-cosθ^2)/(1+cosθ)

  6. anonymous
    • one year ago
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    =(1-cosθ)(1+cosθ)/(1+cosθ) then we simplfy we know that a^2 - b^2=(a-b)(a+b) @Madgirlwithabluebox

  7. anonymous
    • one year ago
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    so we get after simplifying the result =(1-cosθ) did u understand @Madgirlwithabluebox

  8. Madgirlwithabluebox
    • one year ago
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    Uh no? I get that since there was (1+cosθ)/(1+cosθ) you simplified and got the answer but i dont understand anything else

  9. anonymous
    • one year ago
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    so? You understood it or no now ?

  10. Madgirlwithabluebox
    • one year ago
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    I think ,

  11. freckles
    • one year ago
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    does this make sense: assuming y not -1 simplifying (1-y^2)/(1+y) \[\frac{1-y^2}{1+y}=\frac{(1-y)(1+y)}{1+y}=\frac{\cancel{(1+y)}(1-y)}{\cancel{1+y}}=1-y\]

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