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TheYankee

  • one year ago

Check my work on rational expressions? medal!

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  1. TheYankee
    • one year ago
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    I solved this equation

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  2. TheYankee
    • one year ago
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    And ended up with 3(x-1) 2x-1 But I'm very unsteady with these sorts of things. Check my work?

  3. anonymous
    • one year ago
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    first, factor the denominator of the first rational function. From that you'll know the common denominator of both the functions.

  4. anonymous
    • one year ago
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    I'm trying to solve it now, and I'll check if we got the same thing

  5. TheYankee
    • one year ago
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    Factored, isn't it (2x-1)(x-3)? Then the x-3s would cancel out.

  6. anonymous
    • one year ago
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    nope, it should be (2x+1)(x-3)

  7. TheYankee
    • one year ago
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    Oops! Sorry. that's what I meant; typo. The buttons are right next to each other lol

  8. anonymous
    • one year ago
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    so it will look like this: |dw:1433537147204:dw| then since they already have the same denominator, it will be like this: |dw:1433537285450:dw|

  9. TheYankee
    • one year ago
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    Would the numerator end up as x+1, or am I taking things to literally?

  10. TheYankee
    • one year ago
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    *too

  11. anonymous
    • one year ago
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    hmm let's see.. 3x-2-(2x+1) --> remove the brackets first 3x-2-2x-1 --> apply the operations with like terms, what is 3x-2x? and what is -2-1?

  12. TheYankee
    • one year ago
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    Oh! 1x-3 ( or just x-3), then, not 1. (I'm so awful at math....Thanks for the help..)

  13. anonymous
    • one year ago
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    ^_^ you're not done yet ! so the numerator will be x-3, and you also have x-3 in the denominator, so it means, they will cancel out and you'll end up with..?

  14. TheYankee
    • one year ago
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    1 over 2x+1?

  15. anonymous
    • one year ago
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    yes :)

  16. TheYankee
    • one year ago
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    Thank you sooooo much.... You don't realise how much good you've just done me!!!!

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spraguer (Moderator)
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is replying to Can someone tell me what button the professor is hitting...

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