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cutiecomittee123
 one year ago
What are the coordinates to the solution that lays in quadrant 1?
x^2y^2=25
x+y=25
cutiecomittee123
 one year ago
What are the coordinates to the solution that lays in quadrant 1? x^2y^2=25 x+y=25

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0All coordinates in quadrant 1 are positive

cutiecomittee123
 one year ago
Best ResponseYou've already chosen the best response.0I tried squaring the second equation and then adding both equations together, which essentially canceled out the y^2's so then I solved for x but came up with an odd number.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\(x^2y^2=(xy)(x+y)=25\) now use the second equation x+y=25 hope this is enough, :)

cutiecomittee123
 one year ago
Best ResponseYou've already chosen the best response.0thanks for that but what do I do with that information?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0next step would be: xy=1 x+y=25

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0then 2x=26 x=13 y=12

cutiecomittee123
 one year ago
Best ResponseYou've already chosen the best response.0so you basically took the square root of the top equation

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i used the fact that a^2b^2=(ab)(a+b)

cutiecomittee123
 one year ago
Best ResponseYou've already chosen the best response.0how did 25 go to 1?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0if in (xy)(x+y)=25 you substitute the value of (x+y) from second equation, you get (xy)25=25 or xy=1

perl
 one year ago
Best ResponseYou've already chosen the best response.0Nice solution. Another way to do it is solve for x in the second equation and substitute it in the first equation. That gives you a quadratic and more work involved to get the answer.

cutiecomittee123
 one year ago
Best ResponseYou've already chosen the best response.0Yeah I figured it out though:) (13,12)
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