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Jravenv

  • one year ago

Can you assist me with this please? Screepcap in comments

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  1. Jravenv
    • one year ago
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  2. anonymous
    • one year ago
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    show what you have done so far

  3. Jravenv
    • one year ago
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    I haven't done anything, I don't really understand the question to be honest. If you could help me with a step by step process I'd really appreciate it.

  4. anonymous
    • one year ago
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    Ok, first we have the problem below and we want to isolate x, i.e. find an expression for x in terms of "a" and "b". \[\frac{5a}{x} = \frac{5b}{x-1}\]

  5. Jravenv
    • one year ago
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    How do I do that? o.o

  6. anonymous
    • one year ago
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    the fist step is to multiply both sides by \(x(x-1)\), so we get: \[x(x-1)\frac{5a}{x} = x(x-1)\frac{5b}{x-1}\] \[5a(x-1) = 5bx\]

  7. anonymous
    • one year ago
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    now you expand the parethesis: \[5ax - 5a = 5bx\] \[5ax - 5bx = 5a\] \[5x(a-b) = 5a\] \[x(a-b) = a\]

  8. anonymous
    • one year ago
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    now, what you do?

  9. Jravenv
    • one year ago
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    Get the x to the equal sign, so would I divide both sides by x?

  10. anonymous
    • one year ago
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    No... now, in order to find and expression to x, that is, find something like this: "x = ...", just divide both sides by \(a-b\)

  11. anonymous
    • one year ago
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    So we get \[x = \frac{a}{a-b}\]

  12. Jravenv
    • one year ago
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    That's a really complicated process, I kind of get it but for future references would you mind helping me to comprehend how you get an expression for the terms of "a" and "b".

  13. anonymous
    • one year ago
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    Sure, but you should learn this, it's very important, you are going to use it everywhere in math

  14. anonymous
    • one year ago
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    It's just a process of isolating x to one side and everything else to the other side

  15. Jravenv
    • one year ago
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    I'm not good at math at all, I've tried to learn all this, but I have serious troubles comprehending this type of stuff. I don't have a teacher because I'm homeschooled also so I'm sort of stuck with OpenStudy.

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