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anonymous
 one year ago
Simplify: (sin Θ − cos Θ)^2 + (sin Θ + cos Θ)^2.
Options include:
sin^2 Θ
cos^2Θ
0
2
anonymous
 one year ago
Simplify: (sin Θ − cos Θ)^2 + (sin Θ + cos Θ)^2. Options include: sin^2 Θ cos^2Θ 0 2

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So what would you get should you foil out both of those?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok I'm going to let sin Θ = x and cos Θ = y (xy)(xy) (x^2xy+y^2) (x+y)(x+y) (x^2 +xy+y^2)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so (sin Θ^2  sin Θ times cos Θ + cos Θ^2) + (sin Θ^2 + sin Θ times cos Θ + cos Θ^2) but what is sin theta times cos theta??

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Well, you should have a \(2\sin(\theta)\cos(\theta)\) and a \(+2\sin(\theta)\cos(\theta)\), so those would cancel anyway, we don't need to worry about them.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ohh I forgot the outside values

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0But once you cancel and combine everything, you would have \(2\sin^{2}(\theta) + 2\cos^{2}(\theta) = 2(\sin^{2}(\theta) + \cos^{2}(\theta))\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay so it should be (sin^2 theta + cos^2 theta) + (sin^2 theta + cos^2 theta)? And the pythagorean identity says that sin^2 theta + cos^2 theta = 1, so 1 + 1 = 2?

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.0i have seen this question here over and over lol did teacher run out of problems or something hehe
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