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anonymous
 one year ago
yep
anonymous
 one year ago
yep

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Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1http://prntscr.com/7dmxnk what quadrant ?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1dw:1433549520753:dw draw a right triangle in 3rd quadrant sin = opposite over hyp now apply Pythagorean theorem to find 3rd side of right triangle a^2 + b^2 = c^2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i don't get it sorry

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1given is sin = 2/3 sin = opposite over hypotenusedw:1433549857252:dw that's how we have to draw a right triangle in 3rd quadrant \[\rm sin \rm \theta = \frac{ opposite }{ hypotenuse }~~~~ \cos \theta = \frac{ adjacent }{ hypotenuse } ~~\tan \theta = \frac{ opposite }{ adjacent }\]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.12 is opposite of angle a and longest side is hyp so that's how \[\huge\rm sin a = \frac{ 2 }{ 3 }=\frac{ opposite }{ hypotenuse }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so cos =?/3 and tan =2/?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1that's why first you should find 3rd side of right triangle a^2 +b^2 =c^2 substitute value solve for 3rd side

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1hypotenuse is the longest side of right triangle which is c in the formula

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1\[\huge\rm (2)^2 + b^2 = 3^2 \] \[\huge\rm b^2 = 9 4\] b^2 is 5 what's b ?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1what did you substitute 5 ? b square = 5 not b b^2 = 5 how would you solve for b ? how would u cancel square ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so sin=2/3 cos 5/3 tan 2/5

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1\[\huge\rm (2)^2 + b^2 = 3^2 \] \[\huge\rm b^2 = 9 4\] \[\huge\rm b^2 = 5\] b square is 5 not b take square root both sides to cancel out square

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1square rO_Ot not square

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1\[\huge\rm x^2 = 4\] solve for x

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1aww @Loser66 is here :) can you help i have to go 4 prayer :3

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1you should take square root both sides \[\huge\rm \sqrt{ x^2} =\sqrt{ 4}\]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1\[\huge\rm (2)^2 + b^2 = 3^2 \] \[\huge\rm b^2 = 9 4\] \[\huge\rm \sqrt{ b^2} = \sqrt{5}\] same here take square root both sides

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1alright cya and remember if you get radical sign at the bottom then multiply both top and bottom by it's conjugate :3

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1so cos =?/3 and tan =2/? socossqrt{5}/3 it's in 3rd quadrant so cos and sin values are negative tan = opposite over adjacent 2/sqrt{5} multiply top and bottom by sqrt{5} then solve

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1you can't multiply square root with constant term

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1\[\frac{ 2 }{ \sqrt{5}} \times \frac{\sqrt{5}}{\sqrt{5}} = ???\]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.12 times sqrt{2} is not equal to 10

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1exact form not a decimal

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.12 times sqrt{5} =2sqrt{5} solve denominator

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1how did you get sqrt{2} ??

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1my question is how did you get sqrt{2} ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0can we move one to the question please

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.12 times sqrt{5} = 2sqrt{5} sqrt{5} times sqrt{5} = ??

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1sqrt{5} times sqrt{5} not equal to 25

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1remember we are in3rd quadrant where tan is positive

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1csc =1/sin replace sin by its value multiply top with the reciprocal of the bottom

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.11/sin sin =2/3 substitute

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1\[\huge\rm \frac{ a }{ \frac{ b }{ c } } = a \times \frac{ c }{ b }\] like this !!!

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1\[\huge\rm \frac{ a }{ \frac{ b }{ c } } = a \times \frac{ c }{ b }\] look at this
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