A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

anonymous

  • one year ago

yep

  • This Question is Closed
  1. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @Nnesha

  2. Nnesha
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    http://prntscr.com/7dmxnk what quadrant ?

  3. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

  4. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    does this help

  5. Nnesha
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    yes you forgot 3 there

  6. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    my bad

  7. Nnesha
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1433549520753:dw| draw a right triangle in 3rd quadrant sin = opposite over hyp now apply Pythagorean theorem to find 3rd side of right triangle a^2 + b^2 = c^2

  8. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i don't get it sorry

  9. Nnesha
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    given is sin = -2/3 sin = opposite over hypotenuse|dw:1433549857252:dw| that's how we have to draw a right triangle in 3rd quadrant \[\rm sin \rm \theta = \frac{ opposite }{ hypotenuse }~~~~ \cos \theta = \frac{ adjacent }{ hypotenuse } ~~\tan \theta = \frac{ opposite }{ adjacent }\]

  10. Nnesha
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    -2 is opposite of angle a and longest side is hyp so that's how \[\huge\rm sin a = -\frac{ 2 }{ 3 }=\frac{ opposite }{ hypotenuse }\]

  11. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    so cos =-?/3 and tan =-2/?

  12. Nnesha
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    that's why first you should find 3rd side of right triangle a^2 +b^2 =c^2 substitute value solve for 3rd side

  13. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    So -2^2+-3^2=13^2

  14. Nnesha
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    hypotenuse is the longest side of right triangle which is c in the formula

  15. Nnesha
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    c=3 a=-2 solve for b

  16. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    b=5

  17. Nnesha
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    \[\huge\rm (-2)^2 + b^2 = 3^2 \] \[\huge\rm b^2 = 9 -4\] b^2 is 5 what's b ?

  18. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    (-2)^2+5^=3^

  19. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    3^2

  20. Nnesha
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    what did you substitute 5 ? b square = 5 not b b^2 = 5 how would you solve for b ? how would u cancel square ?

  21. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    so sin=-2/3 cos -5/3 tan -2/5

  22. Nnesha
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    \[\huge\rm (-2)^2 + b^2 = 3^2 \] \[\huge\rm b^2 = 9 -4\] \[\huge\rm b^2 = 5\] b square is 5 not b take square root both sides to cancel out square

  23. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    so 20??

  24. Nnesha
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    reread

  25. Nnesha
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    square rO_Ot not square

  26. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i don't get sorry

  27. Nnesha
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    \[\huge\rm x^2 = 4\] solve for x

  28. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    -2

  29. Nnesha
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    how did you get -2 ?

  30. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    x^2-4=2

  31. Nnesha
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    aww @Loser66 is here :-) can you help i have to go 4 prayer :3

  32. Nnesha
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    you should take square root both sides \[\huge\rm \sqrt{ x^2} =\sqrt{ 4}\]

  33. Nnesha
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    \[\huge\rm (-2)^2 + b^2 = 3^2 \] \[\huge\rm b^2 = 9 -4\] \[\huge\rm \sqrt{ b^2} = \sqrt{5}\] same here take square root both sides

  34. Nnesha
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    alright cya and remember if you get radical sign at the bottom then multiply both top and bottom by it's conjugate :3

  35. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    thanks then what

  36. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @sdfgsdfgs

  37. Nnesha
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    so cos =-?/3 and tan =-2/? so-cos-sqrt{5}/3 it's in 3rd quadrant so cos and sin values are negative tan = opposite over adjacent -2/sqrt{5} multiply top and bottom by sqrt{5} then solve

  38. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    -10/25

  39. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @Nnesha

  40. Nnesha
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    you can't multiply square root with constant term

  41. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    what

  42. Nnesha
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    \[\frac{ -2 }{ \sqrt{5}} \times \frac{\sqrt{5}}{\sqrt{5}} = ???\]

  43. Nnesha
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    -2 times sqrt{2} is not equal to 10

  44. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    -2.828

  45. Nnesha
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    exact form not a decimal

  46. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    -2 sqrt 2

  47. Nnesha
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    -2 times sqrt{5} =-2sqrt{5} solve denominator

  48. Nnesha
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    how did you get sqrt{2} ??

  49. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    -2 √2

  50. Nnesha
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    how did you get that ?

  51. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    -2 sqrt 2= -2 √2

  52. Nnesha
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    my question is how did you get sqrt{2} ?

  53. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    u said it

  54. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    can we move one to the question please

  55. Nnesha
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    http://prntscr.com/7dnps2

  56. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    25

  57. Nnesha
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    -2 times sqrt{5} = -2sqrt{5} sqrt{5} times sqrt{5} = ??

  58. Nnesha
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    sqrt{5} times sqrt{5} not equal to 25

  59. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    5

  60. Nnesha
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    yes right

  61. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    then what

  62. Nnesha
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    that's tan

  63. Nnesha
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    csc = ? identity

  64. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    5/3?

  65. Nnesha
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    remember we are in3rd quadrant where tan is positive

  66. Nnesha
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    tan =2sqrt{5}/5

  67. Nnesha
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    csc =1/sin replace sin by its value multiply top with the reciprocal of the bottom

  68. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    2/3?

  69. Nnesha
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    1/sin sin =-2/3 substitute

  70. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    1/(-2/3) @Nnesha

  71. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    3/-2/3

  72. Nnesha
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    \[\huge\rm \frac{ a }{ \frac{ b }{ c } } = a \times \frac{ c }{ b }\] like this !!!

  73. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    1x-2/3

  74. Nnesha
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    \[\huge\rm \frac{ a }{ \frac{ b }{ c } } = a \times \frac{ c }{ b }\] look at this

  75. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.