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LynFran

  • one year ago

please help me prove this identity im stuck not geting it out at all! (1+tanx+cotx)(cosx-sinx)=(cscx/sec^2x -secx/csc^2x)

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  1. anonymous
    • one year ago
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    \[(1+tanx+cotx)(cosx-sinx) = \frac{ cscx }{ \sec^{2}x }-\frac{ secx }{ \csc^{2}x }\] Is this correct?

  2. LynFran
    • one year ago
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    yes

  3. anonymous
    • one year ago
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    Loser had the right idea posted, which he deleted for some reason. You can expand the left hand side and it will almost immediately lead you to your solution.

  4. Loser66
    • one year ago
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    I didn't. He posted twice in different section and my comment is in other, not here.

  5. anonymous
    • one year ago
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    Oh, okay, my bad.

  6. Loser66
    • one year ago
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    http://openstudy.com/study#/updates/5572460ce4b0365b53eee5da

  7. anonymous
    • one year ago
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    Im just messing everything up today, I apologize, Loser.

  8. Loser66
    • one year ago
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    @Concentrationalizing no need to apologize. I am cool.

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